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Basile [38]
3 years ago
12

An adult elephant has a mass of about 5.0 tons. An adult elephant shrew has a mass of about 50 grams. How far r from the center

of the Earth should an elephant be placed so that its weight equals that of the elephant shrew on the surface of the Earth
Physics
1 answer:
Diano4ka-milaya [45]3 years ago
4 0

Answer:

2023857702.507m

Explanation:

f=\frac{GMm}{r^{2} }

recall from newton's law of gravitation

G=gravitational constant

mshew=50g

melephant=5*10^3kg

rearth=radius of the earth 6400km or 6400000m

mearth= masss of the earth

Gm(shrew)m(earth)/r(earth)^2 = Gm(elephant)m(earth)/r^2

strike out the left hand side and right hand side variables

m(shrew)/r(earth)^2 = m(elephant)/r^2

r^2 = m(elephant).r(earth)^2 / m(shrew)       .........make r^2 the subject of the equation

r^2=(5*10^{3} *(6400000)^{2} )/.05

r^2=40960000000000

r=2023857702.507m

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Fossil fuels has been used more in the existing world. Why?
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3 0
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How high must you lift a 25 Newton book for it to have the same increase in potential energy as a 20 Newton book that was lifted
Annette [7]

Given :

An object with weight 20 N was lifted to 0.5 meters.

To Find :

How high must you lift a 25 Newton book for it to have the same increase in potential energy as the given book.

Solution :

Since both have same potential energy :

P.E_2 = P.E_1\\\\W_2h_2 = W_1h_1

Putting all given values in above equation :

25h_2 = 20\times 0.5\\\\h_2 = \dfrac{20\times 0.5}{25}\\\\h_2 = 0.4\ m

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4 0
3 years ago
What multiple of the time constant τ gives the time taken by an initially uncharged capacitor in an RC series circuit to be char
podryga [215]

Answer:

  t / τ₀ = 2.9

the time constant has to be multiplied by approximately three

Explanation:

The expression for long of a capacitor is

    q = q₀ (1- e (-t/τ₀)

Where q is the charge and τ₀ is the time constant.  What is found for when the initial capacitor charge at 63.5% (e⁻¹) of the maximum charge

In our case we are asked that the load be 94.5%, this means that

    q/q₀ = 94.5%

    q/q₀ = 0.945

Let's replace and calculate

    q/q₀ = 1 - e (-t/τ₀)

    0.945 = 1 - e (-t/τ₀)

    (-t /τ₀) = ln (1 -0.945) = ln (0.055)

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the time constant has to be multiplied by approximately three for this charge

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4 years ago
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3 0
3 years ago
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