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Anni [7]
3 years ago
5

vector a having mignitude 3.2 makes 50degre with x-axis and vector b with magnitude 5.2 makes 110degre with x-axis what is the m

agnitude of their dot and cross product?
Physics
1 answer:
Svetllana [295]3 years ago
8 0
Yep ask google good idea
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The gravitational force between two objects will be greatest in which of the following situations?
Kobotan [32]

Answer:

Explanation:

Gravitational law states that, the force of attraction or repulsion between two masses is directly proportional to the product of the two masses and inversely proportional to the square of their distance apart.

So,

Let the masses be M1 and M2,

F ∝ M1 × M2

Let the distance apart be R

F ∝ 1 / R²

Combining the two equation

F ∝ M1•M2 / R²

G is the constant of proportional and it is called gravitational constant

F = G•M1•M2 / R²

So, to increase the gravitational force, the masses to the object must be increased and the distance apart must be reduced.

So, option c is correct

C. Both objects have large masses and are close together.

8 0
3 years ago
An electric motor converts electrical energy into (blank) energy
Delicious77 [7]

Answer:

Mechanical

Explanation:

5 0
3 years ago
A rock is dropped from the edge of a cliff into a pool of water. Assume free-fall acceleration is 10 m/s per second, and air res
il63 [147K]

Answer:

20 m

Explanation:

From the equation of motion,

S = ut+1/2gt²................................. Equation 1

Where S = Height, u = initial velocity, t = time, g = acceleration due to gravity.

Note: Because the rocked is being dropped from a height, acceleration due to gravity is positive (g), and initial velocity (u) is negative

Given: t = 2.0 s, g = 10 m/s², u = 0 m/s (dropped from height)

Substituting into equation 1

S = 0(2) + 1/2(10)(2)²

S = 5(4)

S = 20 m

Hence the height of the the cliff above the pool is 20 m

7 0
3 years ago
3) connect two lamps to a power supply in series and current drawn from the power supply is is. connect the same two lamps in pa
notka56 [123]

The current drawn by the series circuit is(R₁ + R₂)/R₁R₂  times the current drawn by the parallel circuit.

Let the resistance of the two lamps are R₁ and R₂.

Then the equivalent resistance in series combination is: R = R₁ + R₂.

And,  the equivalent resistance in parallel combination is:

r = R₁R₂/(R₁ + R₂).

So, if the supply voltage is V,

Then, current drown in series combination; i_s = V/R = V/(R₁ + R₂)

And, current drown in parallel combination; i_p = V/r = V(R₁ + R₂)/R₁R₂

So ,\frac{i_s}{i_p} = [ V/(R₁ + R₂)] /[V(R₁ + R₂)/R₁R₂]

=  (R₁ + R₂)/R₁R₂

Hence, the  ratio of current drawn in series and current drown in parallel is  (R₁ + R₂)/R₁R₂.  So, he current drawn by the series circuit is(R₁ + R₂)/R₁R₂  times the current drawn by the parallel circuit.

Learn more about electric current here:

brainly.com/question/2264542

#SPJ1

4 0
1 year ago
A 1.0-m long wire is carrying a certain amount of current. The wire is placed perpendicular to a magnetic field of strength 0.20
Marysya12 [62]

For a current-carrying wire running perpendicular to a magnetic field, the magnetic force acting on the wire is given by:

F = ILB

F = magnetic force, I = current, L = wire length, B = magnetic field strength

Given values:

F = 0.60N, L = 1.0m, B = 0.20T

Plug in and solve for I:

0.60 = I(1.0)(0.20)

I = 3.0A

5 0
4 years ago
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