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CaHeK987 [17]
3 years ago
12

Atomic number describes which of the following?

Chemistry
2 answers:
Burka [1]3 years ago
8 0

Answer:

The correct answer is option C.

Explanation:

Atomic weight is defined as sum of protons and neutrons present in the nucleus of an atom of the particular element.It is denoted by A.

Atomic number is defined as total number of protons present in the nucleus of an atom of the particular element. It is denoted by Z.

For an element say with X symbol both atomic weight and number are denoted by: ^{Z}_{A}X.

masha68 [24]3 years ago
6 0
The answer is D hope this helps
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External

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There are many different kinds of stimuli for which is different for every organism, for example, water, light and carbon dioxide are three stimuli and materials needed for photosynthesis in plants to manifest.
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3 0
3 years ago
Newton contributed to astronomy by:
SCORPION-xisa [38]

Answer:  D

Explanation:

This is the answer because everyone knows he discovered gravity and he conducted scientific experiments to prove them which he also used math for

Hope this helps

6 0
3 years ago
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Driving cars lowers the pH of the oceans by _______.
Naddika [18.5K]
A) releasing CO2 that dissolves and forms acid in the oceans (i think i'm sorry if its wrong)
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3 years ago
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Rn-222 has a half-life of 3.82 days. If 25.0 g of Radon-22 was originally present, approximately how many grams would be left af
horsena [70]

Answer:

Approximately 0.39 g or 0.4 g if you're rounding up

Explanation:

15/3.82 = 3.92

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6 0
4 years ago
VA 19.75-g sample was heated by 12.35 calories. The specific heat of the sample is 0.125 cal/g°C. What was the initial temperatu
SOVA2 [1]

Answer:

31.9 °C  

Explanation:

The formula for the heat q absorbed by an object is

q = mCΔT where ΔT = (T₂ - T₁)

Data:

q = 12.35 cal

m = 19.75 g

C = 0.125 cal°C⁻¹g⁻¹

T₂ = 37.0 °C

Calculations

(a) Calculate ΔT

q = mCΔT

12.35 cal = 19.25 g × 0.125 cal°C⁻¹g⁻¹ × ΔT

12.35 = 2.406ΔT °C⁻¹  

ΔT  = 12.35/(2.406 °C⁻¹) = 5.13 °C

(b) Calculate T₂

ΔT = T₂ - T₁

T₁ = T₂ - ΔT = 37.0 °C - 5.13 °C = 31.9 °C

The original temperature was 31.9 °C.

 

6 0
3 years ago
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