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Citrus2011 [14]
3 years ago
7

A particle at rest undergoes an acceleration of 1.5 m/s 2 to the right and 3.7 m/s 2 up. what is its speed after 6.4 s? answer i

n units of m/s.
Physics
1 answer:
Pie3 years ago
3 0
The resultant of the acceleration can be found using:
a = √(ax² + ay²)
a = √(1.5² + 3.7²)
a = 3.99 m/s²

v = u + at, u = 0
v = 3.99 x 6.4
v = 25.5 m/s
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Answer:

a)    L = 3.29 10⁻⁴ H,  b)U = 5.33 10⁻²  J

Explanation:

a) The inductance is a solenoid this given carrier

           L = \frac{N \ \phi_B }{I}

The magnetic field inside the solenoid is

          B = μ₀ \frac{N}{l}  i

hence the magnetic flux

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we substitute in the expression of inductance

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         A = 1.2566 10⁻³ m²

let's calculate

          L = 250² 4π 10⁻⁷ 1.2566 10⁻² / 0.3

          L = 3.29 10⁻⁴ H

b) The stored energy is

           U = ½ L i²

let's calculate

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Read 2 more answers
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