A particle at rest undergoes an acceleration of 1.5 m/s 2 to the right and 3.7 m/s 2 up. what is its speed after 6.4 s? answer i
n units of m/s.
1 answer:
The resultant of the acceleration can be found using:
a = √(ax² + ay²)
a = √(1.5² + 3.7²)
a = 3.99 m/s²
v = u + at, u = 0
v = 3.99 x 6.4
v = 25.5 m/s
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