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likoan [24]
3 years ago
8

Choose the nonmetallic elements from the list. Check all that apply.

Physics
2 answers:
tresset_1 [31]3 years ago
7 0

Answer:

Oxygen, Argon, Carbon

edge2020

NikAS [45]3 years ago
3 0
Polonium, gallium,argon
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if you drop a softball from just above your knee, the kinetic energy of the ball just before it hits the ground is about 1 jule,
ipn [44]
False.

The mass of a softball is approximately 200 g (0.2 kg), while the knees are located approximately at 30 cm (0.3 m) from the ground. It means that the gravitational potential energy of the ball when it is dropped is
U=mgh=(0.2 kg)(9.81 m/s^2)(0.3 m)=0.6 J

This corresponds to the total mechanical energy of the ball at the moment it is dropped, because there is no kinetic energy (the ball starts from rest). Then the ball is dropped, and just before it hits the ground, all this energy is converted into kinetic energy: but energy cannot be created, so its final kinetic energy cannot be greater than 0.6 J.
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3 years ago
In a longitudinal wave, the places where particles of matter are closer together called
Blizzard [7]

Explanation:

I hesitate to articulate upon the highest degree of accuracy!

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4 years ago
After pollination where does a seed grow in a flower?
ozzi

Answer:

the center of the flower or the ovary

3 0
4 years ago
What is the acceleration of a 100 kg object that experience a net force of -10N?
IceJOKER [234]

Answer:

a = -1/10 m/s2

Explanation:

F = m*a

-10N = 100*a

a = -10/100

a = -1/10 m/s2

3 0
3 years ago
Read 2 more answers
A 2 200-kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 4.20 m before coming into contact
Kisachek [45]

Answer:

669042 N upward

Explanation:

W_g = Work done by gravity on pile driver

W_b = Work done by beam

u = Initial velocity

v = Final velocity

m = Mass of pile driver = 2200 kg

g = Acceleration due to gravity = 9.81 m/s²

h = Height the pile driver falls = 4.2 m

d = Bend in beam = 14 cm

Total work done = Change in Kinetic energy

W_g+W_b=\frac{1}{2}m(v^2-u^2)\\\Rightarrow mg(h+d)+Fd=0\\\Rightarrow F=-\frac{mg(h+d)}{d}\\\Rightarrow F=-\frac{2200\times 9.81(4.2+0.14)}{0.14}\\\Rightarrow F=-669042\ N

The force the beam exerts on the pile driver while the pile driver is brought to rest is 669042 N upward

8 0
3 years ago
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