Answer: 16 atm
Explanation:
P1V1 = P2V2
P2 = P1V1/V2
=4 atm x 8.00 L/2.00L = 16 atm
<u>Answer:</u> The concentration of ethyl ethanoate at equilibrium is 
<u>Explanation:</u>
Given values:
Equilibrium concentration of ethanol = 
Equilibrium concentration of ethanoic acid = 

The given chemical equation follows:

The expression of
for above equation follows:
![K_c=\frac{[C_2H_5OH][CH_3COOH]}{[CH_3COOC_2H_5]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BC_2H_5OH%5D%5BCH_3COOH%5D%7D%7B%5BCH_3COOC_2H_5%5D%7D)
Putting values in above expression, we get:
![0.27=\frac{0.42\times 0.42}{[CH_3COOC_2H_5]}](https://tex.z-dn.net/?f=0.27%3D%5Cfrac%7B0.42%5Ctimes%200.42%7D%7B%5BCH_3COOC_2H_5%5D%7D)
![[CH_3COOC_2H_5]=\frac{0.42\times 0.42}{0.27}=0.653mol/dm^3](https://tex.z-dn.net/?f=%5BCH_3COOC_2H_5%5D%3D%5Cfrac%7B0.42%5Ctimes%200.42%7D%7B0.27%7D%3D0.653mol%2Fdm%5E3)
Hence, the concentration of ethyl ethanoate at equilibrium is 
<u>Answer:</u> The IUPAC name of the carboxylic acid formed is ethanoic acid.
<u>Explanation:</u>
The basic rules for naming of organic compounds are :
- First select the longest possible carbon chain.
- The longest possible carbon chain should include the carbons of double or triple bonds.
- The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne by adding the suffix -yne and carboxylic acid by adding the suffix -oic acid.
- The numbering is done in such a way that first carbon of double or triple bond gets the lowest number.
- The carbon atoms of the double or triple bond get the preference over the other substituents present in the parent chain.
For the given chemical reaction, the equation follows:

When hydrolysis of ester takes place, it leads to the formation of an alcohol and a carboxylic acid.
So, when hydrolysis of ethyl ethanoate occurs, it produces ethanol and a 2- Carbon carboxylic acid named as ethanoic acid.
Hence, the IUPAC name of the carboxylic acid formed is ethanoic acid.
Answer:
Option b is show the chemical property of sodium....
1.) Particle B has a greater kinetic energy because when a particle is at higher temperature it contains more energy.
2.) Diagram B best shows the overflow of heat between the particles. It does because of the enclosed space that it is in and how it will circulate in it.
3.) Heat is transferred between object A and B by having object B (warmer) make a reaction with object A (colder).