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artcher [175]
4 years ago
14

In a basic sine curve, where can the zeros NOT be found

Mathematics
1 answer:
horrorfan [7]4 years ago
7 0
I am guessing middle 
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Help I'm not sure if this is the answer?<br><br> (This question is about trigonometric ratios)
dem82 [27]

9514 1404 393

Answer:

  (b) 15.32

Step-by-step explanation:

You can use your triangle sense to answer this.

The side x will always be shorter than the hypotenuse, 20. This eliminates the last two choices.

If the angle is 45°, then the sides are equal at about 0.707 times the length of the hypotenuse. That would make them 0.707×20 = 14.14. Since the angle is greater than 45°, the opposite side will be greater than 14.14. Only one answer choice fits between 14 and 20: the second choice -- 15.32.

__

The mnemonic SOH CAH TOA reminds you of the relation ...

  Sin = Opposite/Hypotenuse

  sin(50°) = x/20

  x = 20×sin(50°) . . . . multiply by 20 to find x

  x ≈ 15.32 . . . . . . . . . use your calculator to evaluate

__

The attachment is intended to show how the triangle side lengths change with angle.

3 0
3 years ago
16pts for help with this math question
diamong [38]
Y=76 x-18
should be the anwer.
6 0
4 years ago
Read 2 more answers
Simplify. 9x^8-18x^6
GrogVix [38]
You cannot simplify this but you can factorise it:

9x^6 (x^2 - 2)
7 0
3 years ago
The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t
zloy xaker [14]

Answer:

103=  p small

plarge = 123

Step-by-step explanation:

We know that the the ratio of the areas is the scale factor squared/

Larger triangle over smaller triangle

72

----- = scale factor ^2

50

simplify by dividing by 2 on top and bottom

36

----- = scale factor ^2

25

Take the square root of each side

sqrt(36)

-------------- = sqrt(scale factor ^2)

sqrt(25)

6

-------------- = scale factor

5

The ratio of the perimeters is the scale factor

p large             6

-------------- = ----------------

 p small                5

Using cross products

6 p large = 5 p small

We know the sum is 226

p large + p small = 226

p large = 226 - p small

We have 2 equation and 2 unknowns

6 p large = 5 p small

Substitute for p large

6 (226 - p small) = 5 p small

1356 - 6 p small = 5 p small

Add 6 p small to each side

1356 = 11 p small

divide by 11

1356/11 =  p small

P large = 226-1356/11

p large = 2486/11-1356/11

plarge = 1130/11

The solution requires whole number answers so

1356/11 =  p small

123.27 which rounds to 123

plarge = 1130/11

plarge = 102.7272 = 103

6 0
3 years ago
Hi guys can some one help me with this question pls this is kinda hard pls upload in a paper i need all answer i will give them
Ulleksa [173]

Answer:

Step-by-step explanation:

3 0
3 years ago
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