All categories

3 years ago

How many grams are in a sample of KOH with 5.34 x 10^24 molecules?

Chemistry

1 answer:

kirill [66]3 years ago

7 0

Answer:

Mass of KOH = 497.78 g

Explanation:

Given data

mass of KOH = ?

number of KOH molecules = 5.34 × 10²⁴

molar mass of KOH = 56.12 g/mol

Solution

1st we find out the number of moles of KOH

<em>number of moles = number of molecules given / Avogadro number </em>

number of moles of KOH = 5.34 × 10²⁴ / 6.022 × 10²³

number of moles of KOH = 8.87 mol

Now we find out the mass of KOH

<em>Mass of KOH = moles × molar mass</em>

Mass of KOH = 8.87 mol × 56.12 g/mol

Mass of KOH = 497.78 g

You might be interested in

After standardizing a NaOH solution, you use it to titrate an HCl solution known to have a concentration of 0.203 M. You perform

jek_recluse [69]

Answer:

0.203 is the mean of the concentration of the HCl solution

Explanation:

You have 5 concentrations. The most appropiate result is the mean of those results. The mean is a statistical defined as the sum of each result divided by the total amount of results. For the results of the problem, the mean is:

0.210 + 0.204 + 0.201 + 0.202 + 0.197 = 1.014 / 5 =

<h3>0.203 is the mean of the concentration of the HCl solution</h3>

8 0

2 years ago

To test the purity of sodium bicarbonate, you dissolve a 3.50g sample in water and add sulfuric acid. if 1.04g of carbon dioxide

Andrews [41]

Answer is: the percent purity of the sodium bicarbonate is 56.83 %.

1. Chemical reaction: 2NaHCO₃ + H₂SO₄ → 2CO₂ + 2H₂O + Na₂SO₄.

2. m(NaHCO₃) = 3.50 g

n(NaHCO₃) = m(NaHCO₃) ÷ M(NaHCO₃).

n(NaHCO₃) = 3.50 g ÷ 84 g/mol.

n(NaHCO₃) = 0.042 mol.

3. From chemical reaction: n(NaHCO₃) : n(CO₂) = 1 : 1.

n(CO₂) = 0.042 mol.

m(CO₂) = 0.042 mol · 44 g/mol.

m(CO₂) = 1.83 g.

4. the percent purity = 1.04 g/1.83 g ·100%.

the percent purity = 56.8 %.

8 0

3 years ago

Question 1 (1 point)<br> ROOTS--What is NOT a root function in plants?

Jlenok [28]

Answer:

deez nuets

Explanation:

bf gm Jr rj if dl if did fll j fll kd golf du is no u to

3 0

3 years ago

How many atoms are in 0.230grams Pb

Brilliant_brown [7]

Its about 11.5hg because if you divide it with the atom it would result to 11.5hg

5 0

2 years ago

What volume (L) of 0.250 M HNO3 is required to neutralize a solution prepared by dissolving 17.5 g of NaOH in 350 mL of water ?

IRINA_888 [86]

<h3>Answer:</h3>

1.75 L HNO₃

<h3>Explanation:</h3>

We are given;

Molarity of HNO₃ as 0.250 M

Mass of NaOH as 17.5 g

Volume of NaOH = 350 mL

We are required to calculate the volume of 0.250 M

We are going to first write the balanced reaction:

NaOH(aq) + HNO₃(aq) → NaNO₃(aq) + H₂O(l)

Then, we calculate the number of moles of NaOH

Moles = Mass ÷ Molar mass

Molar mass of NaOH = 39.997 g/mol

= 17.5 g ÷ 39.997 g/mol

= 0.4375 moles

We can now calculate the number of moles of HNO₃ using the mole ratio from the equation;

Mole ratio of NaOH to HNO₃ is 1 : 1

Therefore, if moles of NaOH are 0.4375 moles then;

Moles of HNO₃ will also be 0.4375 moles

We can now calculate the volume of HNO₃

Morality = Number of moles ÷ Volume

Thus;

Volume = Number of moles ÷ Molarity

= 0.4375 moles ÷ 0.250 M

= 1.75 L

Therefore, the volume of HNO₃ is 1.75 L

5 0

3 years ago

How many grams are in a sample of KOH with 5.34 x 10^24 molecules?​

How many grams are in a sample of KOH with 5.34 x 10^24 molecules?