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4 years ago

How many grams are in a sample of KOH with 5.34 x 10^24 molecules?

Chemistry

1 answer:

kirill [66]4 years ago

7 0

Answer:

Mass of KOH = 497.78 g

Explanation:

Given data

mass of KOH = ?

number of KOH molecules = 5.34 × 10²⁴

molar mass of KOH = 56.12 g/mol

Solution

1st we find out the number of moles of KOH

<em>number of moles = number of molecules given / Avogadro number </em>

number of moles of KOH = 5.34 × 10²⁴ / 6.022 × 10²³

number of moles of KOH = 8.87 mol

Now we find out the mass of KOH

<em>Mass of KOH = moles × molar mass</em>

Mass of KOH = 8.87 mol × 56.12 g/mol

Mass of KOH = 497.78 g

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Explanation :

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Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Mass of }C_2H_5OH\times 1000}{\text{Molar mass of }C_2H_5OH\times \text{Volume of solution (in mL)}}$

Now put all the given values in this formula, we get:

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3 years ago

How many grams are in a sample of KOH with 5.34 x 10^24 molecules?​

How many grams are in a sample of KOH with 5.34 x 10^24 molecules?