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Mumz [18]
3 years ago
13

In the double-slit experiment with electrons, the electrons arrive at the screen in a

Physics
1 answer:
Y_Kistochka [10]3 years ago
4 0

Answer:

B. Wave-like way with a pattern that is wave-like

Explanation:

The double slit experiment when performed with electromagnetic waves, gives a pattern of light lines and dark areas, equally spaced.

In the case of electrons we must use Broglie's duality principle that states that all things have the characteristics of particles and waves together. The characteristic observed in a given experiment depends on the type of experiment, using the relationship

          p = h /λ

Where p is the amount of motion of the particle and λ the wavelength associated with this particle

In consequence of the previous one to the screen it should arrive as a wave with a wave type pattern

Let's review the answer.

A) False. The pattern is wave type

B) True. The whole process is with undulating characteristics

C) False. A wave arrives

D) False. A wave arrives

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True or false the potential energy of a freely object increases as it begins to fall
Eva8 [605]
False, as an object falls its potential energy turns into kinetic energy thus decreasing the potential energy.
3 0
3 years ago
Each element has an atomic number state which is meant by atomic number
netineya [11]

Answer: The atomic number is the number of protons in an atom, and isotopes have the same atomic number but differ in the number of neutrons. The number of protons in an atom is called its atomic number. This number is very important because it is unique for atoms of a given element. All atoms of an element have the same number of protons, and every element has a different number of protons in its atoms.

Explanation:

3 0
2 years ago
Both objects A and D represent fixed, negatively-charged particles of equal magnitude and Object B represents a fixed, positivel
Kipish [7]

Answer:

Option A = 1.

Explanation:

So, in order to solve this question we are given the Important infomation or data or parameters in the question above as;

(1). First, Both objects A and D represent fixed.

(2).  Both objects A and D are negatively-charged particles of equal magnitude.

(3). "Object B represents a fixed, positively-charged particle (equal, but opposite charge from A and D)."

(4). "Object C shows a moving, positively-charged particle."

So, our mission is to determine the arrow that would correctly show the force of attraction or repulsion on object C caused by the other two objects.

We can do that by drawing out the forces of attraction and the resultants. Therefore, CHECK THE ATTACHED FILE/PICTURE FOR THE DRAWINGS.

The forces of attraction due to objects A and B on on object C will be towards themselves. Hence, the resultant is ONE(1).

6 0
3 years ago
Peter’s body supplies a force of 500 N to run up a 10-m hill in 10 s. How much power is involved in Peter’s run up the hill? Exp
shutvik [7]

Answer: 500 Watts

Explanation:

Power P is the speed with which work W is done. Its unit is Watts (W), being 1 W=\frac{1 Joule}{1 s}.

Power is mathematically expressed as:

P=\frac{W}{t} (1)

Where t is the time during which work W  is performed.

On the other hand, the Work W done by a Force F refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.  It is a scalar magnitude, and its unit in the International System of Units is the Joule (like energy). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter (1J=(1N)(1m)=Nm  ).

When the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:  

W=(F)(d) (2)

In this case, we have the following data:

F=500 N

d=10 m

t=10 s

So, let's calculate the work done by Peter and then find how much power is involved:

From (2):

W=(500 N)(10 m) (3)

W=5000 J (4)

Substituting (4) in (1):

P=\frac{5000 J}{10 s} (5)

Finally:

P=500 W

3 0
2 years ago
A 1200 kg car is brought from 25 m/s to 10m/s over a time period of 5 seconds. Determine the force experienced by the car
aleksklad [387]
It's simple.
We know force is the rate of change in momentum.
So F=(mv-mu)/t or F=m(v-u)/t
=1200*(25-10)/5=3600N
7 0
3 years ago
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