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exis [7]
3 years ago
14

An unknown metal has a mass of 86.8 g. When 5040 J of heat are added to the sample, the sample temperature changes by 64.7 ∘ C .

Calculate the specific heat of the unknown metal.
Chemistry
1 answer:
grandymaker [24]3 years ago
4 0

Answer: The specific heat of the unknown metal is 0.897J/g^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed=5040 Joules

m= mass of substance = 86.8 g

c = specific heat capacity = ?

Initial temperature of the water = T_i

Final temperature of the water = T_f

Change in temperature ,\Delta T=T_f-T_i=(64.7)^0C

Putting in the values, we get:

5040=86.8\times c\times 64.7^0C

c=0.897J/g^0C

The specific heat of the unknown metal is 0.897J/g^0C

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An air compressor draws in 1,200 cf of free air at a gauge pressure of 0 psi and a temperature of 70°F. The air is compressed to
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Answer:

The final volume of air after compression: V₂ = 4477.63 L = 158.12 cf

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⇒ T₁ = (70°F − 32) × 5/9 + 273.15 = 294.26 K

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\frac{P_{1}\times V_{1}}{T_{1}} = \frac{P_{2}\times V_{2}}{T_{2}}

→ V_{2} = \frac{P_{1}\times V_{1}\times T_{2}}{T_{1}\times P_{2}}

→ V_{2} = \frac{12.20 psi\times 33980.4 L\times 324.82 K}{294.26 K\times 102.2 psi}

→ V_{2} = 4477.63 L = 158.12 cf

<u>Therefore, the final volume of air after compression: </u><u>V₂ = 4477.63 L = 158.12 cf</u>

7 0
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