Question

How many grams of nacl are required to make 500.0 ml of a 1.500 m solution?

Answer 1

Answer:

43.875 grams of NaCl are required to make 500.0 ml of a 1.500 M solution.

Explanation:

$Moles (n)=Molarity(M)\times Volume (L)$

Moles of NaCl = n

Volume of NaCl solution = 500.0 mL = 0.500 L

Molarity of the NaCl solution  = 1.500 M

$n=1.500 M\times 0.500 L=0.75 mol$

Mass of 0.75 moles of NaCl:

0.75 mol × 58.5 g/mol=43.875 g

43.875 grams of NaCl are required to make 500.0 ml of a 1.500 M solution.

Answer 2

43.83g of nacl are required to make 500.0 ml of a 1.500 m solution.