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Tasya [4]
3 years ago
15

Water flows steadily through a pipe of length L and radius R=75mm. The velocity distribution across the outlet is given by u=uma

x 1− r2 R2 and umax =3m=s. Evaluate the ratio of the x-direction momentum flux at the pipe outlet to that at the inlet.

Physics
1 answer:
ruslelena [56]3 years ago
8 0

Answer:

4/3

Explanation:

Shown in the picture attached

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1. A 700 kg satellite is in orbit 2.4 x 106 meters from the center of the Earth. What is the force of
nevsk [136]

Answer:

4.8 \cdot 10^4 N

Explanation:

The force of gravity acting on the satellite is given by:

F=\frac{GMm}{r^2}

where

G is the gravitational constant

M=5.98\cdot 10^{24} kg is the Earth's mass

m is the mass of the satellite

r is the distance of the satellite from the Earth's centre

Here we have

m = 700 kg

r=2.4\cdot 10^6 m

Substituting into the equation, we find:

F=\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})(700)}{(2.4\cdot 10^6)^2}=4.8 \cdot 10^4 N

<em>Note that the distance mentioned in the problem (2.4 x 10^6 meters) is not realistic, since it is less than the radius of the Earth (6.37 x 10^6 meters).</em>

3 0
3 years ago
the distance a spring will stretch varies directly with how much weight is attached to the spring. If a spring stretches 11 inch
Paha777 [63]
Direct variation involves ration and proportions, so 

you need to set up the proportion:

<span>11 / 75 = x / 65
 
Cross multiplying:

75x = 11*65

x = (11*65)/75

Solving, we get x = 9.533, </span>

<span>which rounds off to 9.5

Therefore, the spring will stretch up to 9.5 inches with 65 attached.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

</span>
4 0
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The metric unit of force is the
Verizon [17]
Newtons. Force is mass times acceleration. Mass is measured in kilograms (kg) and acceleration is measured in meters per second squared (m/s^2.) These units (kg and m/s^2) multiplied together like in the equation force equals mass times acceleration (F=ma) gives a product with Newtons as the unit. 
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He proposed the sun-centered model of the solar system.
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Tin is very weakly attracted to magnets, but is not ferro magnetic. I would say it is magnetic even though it is very weakly attracted to it.
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3 years ago
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