Convert 3 moles of h2o into grams

1 answer:

4 0

To convert 3 mol H2O to grams, just multiply by the molar mass of H2O.

<span>3 mol H2O * 18 g H2O / 1 mol H2O = 54 g H2O

Hope this helped.</span>

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What masses of kbr and water are needed to produce 300. g of a solution that is 3.00 % by mass?

attashe74 [19]

In a solution of KBr and water; KBr is the solute and water is the solvent;
Therefore; to achieve 3% by mass; it means we are going to have 3% of the mass being the solute and the other 97 % being the solvent.
Thus; KBr (solute) = 3/100 × 300 (total mass) = 9 g
Hence; the appropriate masses will be; 9.00 g of KBr and 291 g of water.

8 0

2 years ago

Consider the gas-phase equilibrium A ? B. In a series of experiments, different initial amounts of A and B are mixed together, a

AleksandrR [38]

Answer:

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Explanation:

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3 years ago

A Helium gas in a tube with a volume of 9.583 L under pressure of 4.972 atm at 31.8 c

andre [41]

1.905 moles of Helium gas are in the tube. Hence, option A is correct.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 4.972 atm

V= 9.583 L

n=?

R= $0.082057338 \;L \;atm \;K^{-1}mol^{-1}$