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Nutka1998 [239]
2 years ago
8

Describe the phases of the moon along with a picture.​

Physics
2 answers:
Alex787 [66]2 years ago
5 0

Answer:

The eight Moon phases:

Waxing Crescent: In the Northern Hemisphere, we see the waxing crescent phase as a thin crescent of light on the right. First Quarter: We see the first quarter phase as a half moon. Waxing Gibbous: The waxing gibbous phase is between a half moon and full moon.

The phases of the Moon are the different ways the Moon looks from Earth over about a month. As the Moon orbits around the Earth, the half of the Moon that faces the Sun will be lit up. The different shapes of the lit portion of the Moon that can be seen from Earth are known as phases of the Moon.

<h2>The 8 phases (in order) are:</h2>
  • New moon.
  • Waxing Crescent.
  • First Quarter.
  • Waxing Gibbous.
  • Full moon.
  • Waning Gibbous.
  • Third Quarter.
  • Waning Crescent.

Explanation:

Hope it is helpful....

Rashid [163]2 years ago
3 0

Answer: i think u can put this The phases of the Moon are the different ways the Moon looks from Earth over about a month. As the Moon orbits around the Earth, the half of the Moon that faces the Sun will be lit up. The different shapes of the lit portion of the Moon that can be seen from Earth are known as phases of the Moon

Don't forget to drop a heart have a happy friday

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Answer:

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» 30 N

Explanation:

<u>Given</u> :

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A racetrack has the shape of an inverted cone, as the drawing shows. On this surface the cars race in circles that are parallel
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Answer:

The value of d is 183.51 m.

Explanation:

Given that,

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Normal force acting on the car = N

We need to calculate the value of d

Using component of normal force

The horizontal component of normal force is equal to the gravitational force.

N\cos\theta=mg....(I)

The vertical component of normal force is equal to the centripetal force

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Divided equation (I) by equation (II)

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Put the value of g

\tan\theta=\dfrac{v^2}{g\times d\cos\theta}

v^2=\tan\theta\times g\times d\cos\theta

v^2=g\times d\sin\theta

d=\dfrac{v^2}{g\sin\theta}

Put the value into the formula

d=\dfrac{(34.0)^2}{9.8\times\sin40}

d=183.51\ m

Hence, The value of d is 183.51 m.

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