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Nutka1998 [239]
3 years ago
8

Describe the phases of the moon along with a picture.​

Physics
2 answers:
Alex787 [66]3 years ago
5 0

Answer:

The eight Moon phases:

Waxing Crescent: In the Northern Hemisphere, we see the waxing crescent phase as a thin crescent of light on the right. First Quarter: We see the first quarter phase as a half moon. Waxing Gibbous: The waxing gibbous phase is between a half moon and full moon.

The phases of the Moon are the different ways the Moon looks from Earth over about a month. As the Moon orbits around the Earth, the half of the Moon that faces the Sun will be lit up. The different shapes of the lit portion of the Moon that can be seen from Earth are known as phases of the Moon.

<h2>The 8 phases (in order) are:</h2>
  • New moon.
  • Waxing Crescent.
  • First Quarter.
  • Waxing Gibbous.
  • Full moon.
  • Waning Gibbous.
  • Third Quarter.
  • Waning Crescent.

Explanation:

Hope it is helpful....

Rashid [163]3 years ago
3 0

Answer: i think u can put this The phases of the Moon are the different ways the Moon looks from Earth over about a month. As the Moon orbits around the Earth, the half of the Moon that faces the Sun will be lit up. The different shapes of the lit portion of the Moon that can be seen from Earth are known as phases of the Moon

Don't forget to drop a heart have a happy friday

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Answer:

Sledgehammer A has more momentum

Explanation:

Given:

Mass of Sledgehammer A = 3 Kg

Swing speed = 1.5 m/s

Mass of Sledgehammer B = 4 Kg

Swing speed = 0.9 m/s

Find:

More momentum

Computation:

Momentum = mv

Momentum sledgehammer A = 3 x 1.5

Momentum sledgehammer A = 4.5 kg⋅m/s

Momentum sledgehammer B = 4 x 0.9

Momentum sledgehammer B = 3.6 kg⋅m/s

Sledgehammer A has more momentum

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Setler [38]

Answer:

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Explanation:

8 0
4 years ago
An 888.0 kg elevator is moving downward with a velocity of 0.800 m/s. It decelerates uniformly and comes to a stop in a distance
bagirrra123 [75]

Answer:

The value of tension on the cable T = 1065.6 N

Explanation:

Mass = 888 kg

Initial velocity ( u )= 0.8 \frac{m}{sec}

Final velocity ( V ) = 0

Distance traveled before come to rest = 0.2667 m

Now use third law of motion V^{2} = u^{2} - 2 a s

Put all the values in above formula we get,

⇒ 0 = 0.8^{2} - 2 × a ×0.2667

⇒ a = 1.2 \frac{m}{sec^{2} }

This is the deceleration of the box.

Tension in the cable is given by T = F = m × a

Put all the values in above formula we get,

T = 888 × 1.2

T = 1065.6 N

This is the value of tension on the cable.

5 0
3 years ago
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3 years ago
What will be the final temperature if a 4.00 g silver ring at 41.0◦C if it gives off 18.0 J of heat to the surroundings? The spe
Eduardwww [97]

Answer:

Final temperature, T_f=21.85^{\circ}

Explanation:

Given that,

Mass of silver ring, m = 4 g

Initial temperature, T_i=41^{\circ}C

Heat released, Q = -18 J (as heat is released)

Specific heat capacity of silver, c=0.235\ J/g\ C

To find,

Final temperature

Solution,

The expression for the specific heat is given by :

Q=mc\Delta T

Q=mc(T_f-T_i)

T_f=\dfrac{-Q}{mc}+T_i

T_f=\dfrac{-18}{4\times 0.235}+41

T_f=21.85^{\circ}

So, the final temperature of silver is 21.85 degrees Celsius.

5 0
3 years ago
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