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Bond [772]
3 years ago
13

Is the normal force equivalent to the weight of an object?

Physics
1 answer:
Greeley [361]3 years ago
4 0

Answer:

No.

Explanation:

If there are no applied forces, normal force is usually equivalent to the weight of the object but if there are outside force (force that makes the object to move) especially if it's inclined, then the inclined force would then affect the normal force.

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I have four questions.
Inga [223]

Answer:

The potential energy of the ball is 784 joules. And the kinetic energy of it is 392 while falling halfway down.

Explanation:

PE = mass (2kg) * Gravitational acceleration (9.8 m/s^2)* height (40 meters)

KE = 1/2 mass (1 kg) * velocity^2 (19.8)

7 0
4 years ago
Read 2 more answers
What happens in a tug of war if the net forces are balanced and why?
FinnZ [79.3K]

Answer:

Balanced forces are responsible for unchanging motion. Balanced forces are forces where the effect of one force is cancelled out by another. A tug of war, where each team is pulling equally on the rope, is an example of balanced forces. The forces exerted on the rope are equal in size and opposite in direction.

Explanation:

6 0
4 years ago
How can a force change the motion of an object that is already moving?
lara [203]

Answer:They may cause motion to change

Explanation:They may cause motion; they may also slow, stop, or change the direction of motion of an object that is already moving. Since force cause changes in the speed or direction of an object, we can say that forces cause changes in velocity. Remember that acceleration is a change in velocity.

7 0
3 years ago
Can sound travel through a tree
Marizza181 [45]

Answer:

not sure but i think yes

Explanation:

sound waves

7 0
3 years ago
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A piece of gum is stuck to the outer edge of a horizontal turntable, which is revolving at a constant speed. The shadow of the g
cestrela7 [59]

Answer:

angular frequency of the table must be same as the frequency of the projection of the gum on the wall

Explanation:

Since we know that the projection on the wall is the vertical component of the position of the gum on the rotating table

So here we will say

y = R sin\theta

so the angle made by the radius vector depends on the angular frequency of the disc by which it is rotating

So we can say

\theta = \omega t

so here we can say

y = R sin(\omega t)

so here we can say that

angular frequency of the table must be same as the frequency of the projection of the gum on the wall

7 0
4 years ago
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