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FrozenT [24]
4 years ago
11

What is 52,427 in scientific notation?

Physics
1 answer:
Shkiper50 [21]4 years ago
7 0

Answer: Why is 52,427 written as 5.2427 x 104 in scientific notation

PLEASE BRAINLIEST

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An object is thrown upwards with a velocity of 3 meters per second, such that the only force acting on it is gravity (accelerati
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Answer:

Correct answer:  A.)  V = - 16.6 m/s down

Explanation:

Given:

V₀ = 3 m/s  initial velocity

t = 2 seconds

g = 9.8 m/s²

V(t) = V(2) = ?

The movement described is a vertical upward shot

For velocity at any time is valid the next formula

V = V₀ - g · t

V = 3 - (9.8 · 2) = 3 - 19.6 = - 16.6 m/s down

Under condition that it has a enough drop height with respect to the ejection point.

God is with you!!!

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What is the origin of physics
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Durning which type of process does pressure remain consistent
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Answer:

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Explanation:

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3 years ago
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If you are trying to get ketchup out of the bottle, the best way to do it is to turn the bottle upside down and give the bottle
Igoryamba

Answer:

Explanation:

A body remains at rest or in motion unless or until an external force is applied. This is called Law of Inertia

Now When ketchup bottle is turned upside down and smack is applied to it, it causes the ketchup to start moving thereby disturbing its motion of rest and provide its motion.

And according to the first law state of rest is broken by applying an external force.

                               

3 0
3 years ago
Projectiles that strike objects are good examples of inelastic collisions. A 0.1 kg nail driven by a gas powered nail driver col
Ratling [72]
In an inelastic collision, only momentum is conserved, while energy is not conserved.

1) Velocity of the nail and the block after the collision
This can be found by using the total momentum after the collisions:
p_f=(m+M)v_f=4.8 kg m/s
where
m=0.1 kg is the mass of the nail
M=10 kg is the mass of the block of wood
Rearranging the formula, we find v_f, the velocity of the nail and the block after the collision:
v_f= \frac{p_f}{m+M}= \frac{4.8 kg m/s}{0.1 kg+10 kg}=  0.48 m/s

2) The velocity of the nail before the collision can be found by using the conservation of momentum. In fact, the total momentum before the collision is given only by the nail (since the block is at rest), and it must be equal to the total momentum after the collision:
p_i = mv_i = p_f
Rearranging the formula, we can find v_i, the velocity of the nail before the collision:
v_i =  \frac{p_f}{m}= \frac{4.8 kg m/s}{0.1 kg}=48 m/s
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4 years ago
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