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FrozenT [24]
3 years ago
11

What is 52,427 in scientific notation?

Physics
1 answer:
Shkiper50 [21]3 years ago
7 0

Answer: Why is 52,427 written as 5.2427 x 104 in scientific notation

PLEASE BRAINLIEST

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A tube of water is open on one end to the environment while the other end is closed. The height of the water relative to the bas
Andreas93 [3]

Answer:

<em>1.06 atm</em>

Explanation:

On the open end of the tube, the pressure will be the sum of atmospheric pressure and the pressure due to the height of water

The pressure due to a height of water = ρgh

where ρ is the density of water = 1000 kg/m^3

g is the acceleration due to gravity = 9.81 m/s^2

h is the height of the water column

The height of water column on the open end = 100 cm = 1 m

pressure on this end = ρgh = 1000 x 9.81 x 1 = 9810 Pa

Atmospheric pressure = 101325 Pa

The total pressure on the open end =  101325 Pa + 9810 Pa = <em>111135 Pa</em>

The pressure due to the water column on the closed end = ρgh

The height of the water in the closed end = 40 cm = 0.4 m

The pressure due to this column of water = 1000 x 9.81 x 0.4 = <em>3924 Pa</em>

The resultant pressure on the water on the top of the closed end of the tube = 111135 Pa - 3924 Pa =<em> 107211 Pa</em>

In atm unit, this pressure = 107211/101325 = <em>1.06 atm</em>

7 0
3 years ago
Which measurement tool is used to find the volume of a small piece of granite? Select one: a. thermometer b. metric ruler c. gra
Natalka [10]

Answer:

Explanation:

c. graduated cylinder

3 0
3 years ago
Whais the cause of necular bomb ​
coldgirl [10]

Answer:

The atomic bomb, is as defined by britannica.com “a deadly weapon caused by the sudden release of energy after the splitting, or fission, of the nuclei of heavy elements like uranium.” In 1945, the United States (US) dropped two atomic bombs, one in Hiroshima and the other in Nagasaki ending WWII.

Explanation:

Hope this helps :)

pls mark brainliest :P

6 0
2 years ago
The head of a grass string trimmer has 100 g of cord wound in a light, cylindrical spool with inside diameter 3.00 cm and outsid
faust18 [17]

Answer:

a).11.546J

b).2.957kW

Explanation:

Using Inertia and tangential velocity

a).

w=2250*2\pi *\frac{1}{60}\\ w=235.61

I=\frac{1}{2}*m*((\frac{d_{i} }{2})^{2} +(\frac{d_{e} }{2})^{2})\\m=100g *\frac{ikg}{1000g}=0.1kg\\ d_{i}=3cm*\frac{1m}{100cm}=0.03m \\ d_{e}=18cm*\frac{1m}{100cm}=0.18m\\I=\frac{1}{2}*0.1kg*((\frac{0.03m}{2})^{2} +(\frac{0.18m}{2})^{2})\\I=0.41625x10^{-3}kg*m^{2}

Now using Inertia an w

E=\frac{1}{2}*I*(w)^{2} \\ E=\frac{1}{2}*0.416x10^{-3}*(235.61)^{2} \\E=11.54J

average power=\frac{11.4J}{0.230s}=50.2 W

b).

power=t*w

P=11.5465*0.25*235.61

P=2.957 kW

4 0
3 years ago
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Is any force exerted on the vertical sides of the loop that you used in the experiment and how does it affect the apparent mass?
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What is the dilemma K to 12 graduates face when applying for a job?
their company? Pa help asap po
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