2 kg

A ball of mass m is dropped from rest from a height h and collides elastically with the floor, rebounding to its original height

Jet001 [13]

Answer:

Explanation:

Given

mass m collides elastically with floor and jump to its original height I .e.velocity of rebound is same as the initial velocity

Impulse imparted by steel ball to the ground is given by the change in momentum of steel ball

$J=\Delta P$

and impulse is product of average force and time

so we need time to calculate the average force. So, option e is correct

3 0

3 years ago

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A celestial body orbits the sun. It consists of rock and ice. As it passes close to the sun, the body forms a long tail of dust.

Sergeu [11.5K]

The celestial body that orbits the sun and is consists of rock and ice, that when it passes close to the sun, the body forms a long tail of dust is called a comet. A comet is an icy small body of the solar system, that when it approaches near the sun, it heats up then forms this long tail. The answer would be a comet. Hope this answer helps you.

4 0

4 years ago

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An electric toy with a resistance of 2.50 Ω is operated by a 3.00-V battery. (a) What current does the toy draw? (b) Assuming th

Leno4ka [110]

Answer:

a) The current is i = 1.2 A

b) The charge is Q = 17280 C

c) The energy is E = 43200 J

Explanation:

a) The current is given by the ohm's law wich is:

i = V/R = 3/2.5 = 1.2 A

b) Since the charge is steady we can use the following equation to find the charge amount in that time:

i = Q/t

Q = t*i

Where t is in seconds, so we have 4h * 3600 = 14400 s

Q = 1.2*14400 = 17280 C

c) The energy is the power delivered to the toy multiplied by the time:

P = 1.2*2.5 = 3 W

E = P*t = 3*14400 = 43200 J

7 0

3 years ago

A crane used 250,000 Joules of work to move a beam to the top of a building in 20 seconds. How much power did the crane use?

maria [59]

Answer:

12500W

Explanation:

Given parameters:

Work done = 250000J

Time taken = 20s

Unknown:

Power of the crane = ?

Solution:

Power is the defined as the rate at which work is being done;

Mathematically;

Power = $\frac{work done}{time }$

insert the parameters and solve;

Power = $\frac{250000}{20}$ = 12500W

7 0

3 years ago

sonic is sliding down a frictionless 15m tall hill. He starts at the top with a velocity of 10m/s. At the bottom of the hill he

podryga [215]

Answer:

The maximum speed of sonic at the bottom of the hill is equal to 19.85m/s and the spring constant of the spring is equal to (497.4xmass of sonic) N/m

Energy approach has been used to sole the problem.

The points of interest for the analysis of the problem are point 1 the top of the hill and point 2 the bottom of the hill just before hitting the spring

The maximum velocity of sonic is independent of the his mass or the geometry. It is only depends on the vertical distance involved

Explanation:

The step by step solution to the problem can be found in the attachment below. The principle of energy conservation has been applied to solve the problem. This means that if energy disappears in one form it will appear in another.

As in this problem, the potential and kinetic energy at the top of the hill were converted to only kinetic energy at the bottom of the hill. This kinetic energy too got converted into elastic potential energy .

x = compression of the spring = 0.89

5 0

3 years ago