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Murljashka [212]
3 years ago
15

The current in the circuit shown is 2.0 A.

Physics
2 answers:
andrezito [222]3 years ago
8 0

The value of R3 is A) 10 Ω

larisa [96]3 years ago
3 0

Answer:

Resistor R₃ = 10 Ω

Explanation:

It is given that,

Current flowing in the circuit, I = 2 A

Resistors R₁ = 2 Ω

Resistor R₂ = 3 Ω

Voltage, V = 30 V

We have to find the value of R₃. All three resistors are connected in series. In series combination, the current flowing through the all resistors is same. Firstly, calculating equivalent resistance of three resistors as :

R_{eq}=R_1+R_2+R_3

R_{eq}=2\ \Omega+3\ \Omega+R_3    

R_{eq}=5\ \Omega+R_3..............(1)

Using Ohm's law : V=IR_{eq}

30\ V=2\ A\times (5 + R_{3})

On solving above equation : R_3=10\ \Omega

Hence, the correct option is (A) " 10 Ω "                                            

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\begin{aligned}& (\text{Change in Velocity}) \\ =\; & (\text{Final Velocity}) - (\text{Initial Velocity}) \\ =\; & (-4.0\; {\rm m\cdot s^{-1}}) - (6.0\; {\rm m\cdot s^{-1}}) \\ =\; & (-10\; {\rm m\cdot s^{-1})\end{aligned}.

The change in the linear momentum of the mass would be:

\begin{aligned} & \text{change in momentum} \\ =\; & (\text{mass}) \times (\text{change in velocity}) \\ =\; & 0.58\; {\rm kg} \times (-10\; {\rm m\cdot s^{-1}}) \\  =\; & (-5.8\; {\rm kg \cdot m \cdot s^{-1}})\end{aligned}.

Thus, the magnitude of the change of the linear momentum would be 5.8\; {\rm kg \cdot m \cdot s^{-1}}.

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