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Murljashka [212]
3 years ago
15

The current in the circuit shown is 2.0 A.

Physics
2 answers:
andrezito [222]3 years ago
8 0

The value of R3 is A) 10 Ω

larisa [96]3 years ago
3 0

Answer:

Resistor R₃ = 10 Ω

Explanation:

It is given that,

Current flowing in the circuit, I = 2 A

Resistors R₁ = 2 Ω

Resistor R₂ = 3 Ω

Voltage, V = 30 V

We have to find the value of R₃. All three resistors are connected in series. In series combination, the current flowing through the all resistors is same. Firstly, calculating equivalent resistance of three resistors as :

R_{eq}=R_1+R_2+R_3

R_{eq}=2\ \Omega+3\ \Omega+R_3    

R_{eq}=5\ \Omega+R_3..............(1)

Using Ohm's law : V=IR_{eq}

30\ V=2\ A\times (5 + R_{3})

On solving above equation : R_3=10\ \Omega

Hence, the correct option is (A) " 10 Ω "                                            

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An initial condition has been supplied by the problem: 

s=1.80m when t=0.245s 

<span>This means that it takes the pot 0.245 seconds to travel upward 1.8m. Knowing that the gravitational acceleration acts downward constantly at 9.81m/s^2, and based on this information we can use the formula:

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<span>Now we know the initial velocity of the pot right when it enters the view of the window. We know that at the apex of its flight, the pot's velocity will be v=0, and using this piece of information we can use the kinematic equation:

(v final)=(v initial)+(a)(t) 

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Answer:

<span>1.925m</span>

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If I am to understand this question correctly this is what asks you:

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algol13

Stress required to cause slip on in the direction [ 1 1 0 ] is 7.154 MPa

<u>Explanation:</u>

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