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Murljashka [212]
3 years ago
15

The current in the circuit shown is 2.0 A.

Physics
2 answers:
andrezito [222]3 years ago
8 0

The value of R3 is A) 10 Ω

larisa [96]3 years ago
3 0

Answer:

Resistor R₃ = 10 Ω

Explanation:

It is given that,

Current flowing in the circuit, I = 2 A

Resistors R₁ = 2 Ω

Resistor R₂ = 3 Ω

Voltage, V = 30 V

We have to find the value of R₃. All three resistors are connected in series. In series combination, the current flowing through the all resistors is same. Firstly, calculating equivalent resistance of three resistors as :

R_{eq}=R_1+R_2+R_3

R_{eq}=2\ \Omega+3\ \Omega+R_3    

R_{eq}=5\ \Omega+R_3..............(1)

Using Ohm's law : V=IR_{eq}

30\ V=2\ A\times (5 + R_{3})

On solving above equation : R_3=10\ \Omega

Hence, the correct option is (A) " 10 Ω "                                            

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