First write down all the known variables:
vi = 10m/s
t = 1
a = -9.8m/s^2
vf = ?
Now choose the kinematic equation to relate these variables:
vf = vi + at
vf = (10) + (-9.8)(1)
vf = 0.2 m/s
The speed of the object travelling after a second would be 0.2m/s in reality, however, it is closest to the choice A, which would suffice as the answer for your question.
The answer is a which is zero
The volume of the tire at the given diameter and thickness of tube is determined as 1,128.2 cubic inch.
<h3>What is volume?</h3>
Volume is a scalar quantity expressing the amount of three-dimensional space enclosed by a closed surface.
<h3>
Volume of the tire</h3>
The volume of the tire is the measure of the product of area and thickness of the tire.
The volume of the tire is calculated as follows;
Radius of the tire = 0.5 x 26" = 13"
Volume of the tire = Area x thickness
Volume of the tire = πr² x h
where;
- r is the radius of the tire
- h is the thickness of the tube
Volume of the tire = π(13)² x (2.125)
Volume of the tire = 1,128.2 cubic inch
Thus, the volume of the tire at the given diameter and thickness of tube is determined as 1,128.2 cubic inch.
Learn more about Volume of tire here: brainly.com/question/1972490
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Because it is a fossil fuel.
Answer:
Horizontal distance moved by the person is 3.2 m
And it is independent of the mas of the person
Explanation:
As we know that the speed of the people when it is sliding downwards is given as
![\frac{1}{2}mv^2 = mg(h_2 - h_1)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dmv%5E2%20%3D%20mg%28h_2%20-%20h_1%29)
![v = \sqrt{2g(h_2 - h_1)}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B2g%28h_2%20-%20h_1%29%7D)
![v = \sqrt{2(9.81)(3.2 - 1.5)}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B2%289.81%29%283.2%20-%201.5%29%7D)
![v = 5.77 m/s](https://tex.z-dn.net/?f=v%20%3D%205.77%20m%2Fs)
Now the time taken by the person to hit the water surface is given as
![\frac{1}{2}gt^2 = h](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dgt%5E2%20%3D%20h)
![\frac{1}{2}(9.81)t^2 = 1.5](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%289.81%29t%5E2%20%3D%201.5)
![t = 0.55 s](https://tex.z-dn.net/?f=t%20%3D%200.55%20s)
horizontal distance moved by the person is given as
![d = vt](https://tex.z-dn.net/?f=d%20%3D%20vt)
![d = 5.77 (0.55)](https://tex.z-dn.net/?f=d%20%3D%205.77%20%280.55%29)
![d = 3.2 m](https://tex.z-dn.net/?f=d%20%3D%203.2%20m)