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Anna007 [38]
3 years ago
7

All of the following are part of the electromagnetic spectrum but

Physics
2 answers:
Vedmedyk [2.9K]3 years ago
8 0
D.) Sound waves does not include in Electromagnetic waves.

Hope this helps!

Lera25 [3.4K]3 years ago
3 0
D)sound waves  the electromagnetic spectrum has to do with colors<span />
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wo small containers have a mass of 2.6 g each; one contains 2.4 g of water, the other 1.8 g of alcohol. If the alcohol is poured
vlada-n [284]

Answer:

5.6kg

Explanation:

4 0
2 years ago
If you travel at 3 m/s for 12 seconds, how far did you travel?
ella [17]

Answer:

V=3 m/s

t=12 seconds

S=?

S=V×t

S=3×12

S=36meters

So distance you travel is 36meters.

4 0
2 years ago
Read 2 more answers
A 400.0 kg storage box is held 10 m above ground by a forklift. What is its gravitational potential energy? (PE = mgh)
castortr0y [4]

Answer: D.) 39,200 J

Via the equation of potential energy PE = mgh where m is mass, g is the average gravity on earth and h is the height.  In this case m = 400 kg, g = 9.8, h = 10 m thus:

P.E.=(400kg)(9.8\frac{m}{s^2} )(10m)=39,200 J

P.E.= 39,200 Joules

7 0
3 years ago
Read 2 more answers
Near the end of a marathon race, the first two runners are separated by a distance of 45.6 m. The front runner has a velocity of
morpeh [17]

Answer:17.08 s

Explanation:

Given

distance between First and second Runner is 45.6 m

speed of first runner(v_1)=3.1 m/s

speed of second runner(v_2)=4.65 m/s

Distance between first runner and finish line is 250 m

Second runner need to run a distance of 250+45.6=295.6 m

Time required by second runner t=\frac{295.6}{4.65}=63.56 s

time required by first runner to reach finish line=\frac{250}{3.1}=80.64 s

Thus second runner reach the finish line 80.64-63.56=17.08 s earlier

3 0
3 years ago
The angular speed of digital video discs (DVDs) varies with whether the inner or outer part of the disc is being read. (CDs func
Kitty [74]

Answer:

α = 0.0135 rad/s²

Explanation:

given,

t = 133 min = 133 x 60 = 7980 s

angular speed varies from 570 rpm to 1600 rpm

now,

570 rpm = 570 \times \dfrac{2\pi}{60}

              = 59.69 rad/s

1600 rpm =  = 570 \times \dfrac{2\pi}{60}

              = 167.6 rad/s

using equation of rotational motion

ωf = ωi + αt    

167.6 = 59.7 + α x 7980

α  x 7980 = 107.9

α = 0.0135 rad/s²

8 0
3 years ago
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