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rusak2 [61]
3 years ago
9

If there is a higher concentration of sodium on the left side of a beaker and the membrane is permeable to the sodium, which of

the following will occur?\
Chemistry
2 answers:
Nadya [2.5K]3 years ago
6 0

Answer:

A permeable membrane is a barrier that <em>only allows certain particles to pass</em> through them. Diffusion is a physical process whereby the particles move from a<em> region of higher concentration to a region of lower concentration, </em>and this movement occurs until the equilibrium is reached (same concentration in every region).

<em />

If the membrane is permeable to the sodium, it means that only sodium atoms will be able to migrate from one side to another. And according to difussion phenomenon, sodium atoms will migrate from the side with higher concentration to the side of lower concentration. So, a migration of sodium will occur from the left side of the beaker to the right side of the beaker until the concentration of sodium is the same in both sides.  

Irina-Kira [14]3 years ago
4 0

Answer:

sodium is going to migrate the left to the right side through the membrane

Explanation:

Differences in concentration of sodium produce a movement of sodium through the membrane until reach the equilibrium

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Need help !!!!! ASAP
Korolek [52]
<h2>Hello!</h2>

The answer is:

The new volume is 2.84 L.

V_{2}=2.84L

<h2>Why?</h2>

To solve the problem, we need to remember what STP means. STP means that the gas is at standard temperature and pressure, or 273.15 K (0°C) and 1 atm.

Also, we need to use the Combined Gas Law, since the temperature, the pressure and the volume are being changed.

The Combined Gas Law establishes a relationship between the temperature, the pressure and the volume of an ideal gas using , Gay-Lussac's Law, Charles's Law,  and Boyle's Law.

The law is defined by the following equation:

\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}

Where,

P_{1} is the first pressure.

V_{1} is the first volume.

T_{1} is the first temperature.

P_{2} is the second pressure.

V_{2} is the second volume.

T_{2} is the second temperature.

So, we are given the following information:

V_{1}=2L\\P_{1}=1atm\\T_{1}=0\°C=273.15K\\P_{2}=80kPa=0.8atm\\T_{2}=37\°C=37+273=310K

Then, isolating the new volume, and substituting, we have:

\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}\\\\V_{2}=\frac{P_{1}V{1}}{T_{1}}*\frac{T_{2}}{P_{2}}\\\\V_{2}=\frac{1atm*2L}{273.15K}*\frac{310K}{0.8kPa}=2.84L

Hence, the new volume is 2.84 L.

V_{2}=2.84L

Have a nice day!

4 0
4 years ago
Which type of reaction is represented by this graph?
enot [183]

Answer:  

D. Exothermic.  

Explanation:  

Hello there!

In this case, since the potential energy versus reaction progress diagrams are related to the energetic profile of a chemical reaction, we can set the initial point at the beginning of the reaction as the energy of the reactants and the final point as the energy of the products.

Next, since the change in the enthalpy of a reaction is quantified by subtracting products minus reactants, we can see that the products have less energy than the reactants and therefore ΔH for this reaction is negative, which matches with the definition of D. Exothermic  reaction.

Regards!

7 0
3 years ago
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Please fast I need you to do this question FOR 15POINTS!!!!!!
sergeinik [125]
Ok I’m figuring this one out
4 0
3 years ago
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Volatility and vapor pressure are ________. Volatility and vapor pressure are ________. not related directly proportional to one
alina1380 [7]

Answer:

directly proportional to one another

Explanation:

Volatility refers to how quickly a substance changes from liquid to gas.

If a substance has a high vapour pressure, the substance is highly volatile. Similarly, if a substance has a low vapour pressure, then the substance is much less volatile.

This implies that volatility and vapour pressure gives a direct proportionality.

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3 years ago
the degree to which two separate structures that are close together can be distinguished in an image is called__________.      
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The answer to this is: <span>resolution</span>
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