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evablogger [386]
3 years ago
15

Which of the following represents a case in which you are not accelerating? -Driving 60 miles per hour around a curve -Going fro

m 0 to 60 miles per hour in 10 seconds -Slamming on the brakes to come to a stop at a stop sign -Driving in a straight line at 60 miles per hour
Physics
1 answer:
PIT_PIT [208]3 years ago
8 0

Answer:

Driving in a straight line at 60 miles per hour

Explanation:

In the first case there's an acceleration that modifies the direction of the movement.

In the second case there's a lineal acceleration that increases the speed of the car.

in the third case there's a negative acceleration that reduces the speed of the car.

On the third case the speed is constant so the acceleration is 0 mi/s^2

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3. A large crane lifts a 25,000 kg mass in the air. The amount of work that must be done by the
andreev551 [17]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the concept of Efficiency.

Here we can see that, the Input work is given as 2.2 x 10^7 J and the efficiency is given as 22%

The efficiency is => 22% => 22/100.

so we get as,

E = W(output) /W(input)

hence, W(output) = E x W(input)

so we get as,

W(output) = (22/100) x 2.2 x 10^7

=> W(output) = 0.22 x 2.2 x 10^7 => 0.484 x 10^7

hence, W(output) = 4.84 x 10^6 J

The useful work done on the mass is 4.84 x 10^6 J

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2 years ago
A roller coaster pushes a 25 kg person upward with a force of 300 N. What is the acceleration?
vlada-n [284]
300N/25 kg= divide them for the answer
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3 years ago
The doppler effect is sensitive only to motion along the line of sight. <br> a. True <br> b. False
4vir4ik [10]
Its vey True trust me on this when I say it is
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2 years ago
Explain the relationship between speed, velocity and acceleration
Montano1993 [528]
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8 0
3 years ago
A 57 kg pole vaulter running at 11 m/s vaults over the bar. Her speed when she is above the bar is 1.1 m/s. The acceleration of
kari74 [83]

Answer:

Her altitude as she crosses the bar, h₂ is approximately 6.1 m

Explanation:

The given parameters of the motion of the pole vaulter are;

The mass of the pole vaulter, m = 57 kg

The speed with which the pole vaulter is running, u = 11 m/s

The speed of the pole vaulter when she crosses the bar, v = 1.1 m/s

The acceleration due to gravity, g = 9.8 m/s²

From the total mechanical energy, M.E. equation, we have;

M.E. = P.E. + K.E.

Where;

P.E. = The potential energy of the motion = m·g·h

K.E. = The kinetic energy of the motion = 1/2·m·v²

By the principle of conservation of energy, we have;

The change (loss) in kinetic energy, ΔK.E. = The change (gain) in potential energy, ΔP.E.

ΔK.E. = 1/2·m·(v² - u²)

ΔP.E. = m·g·(h₂ - h₁)

Where;

h₁ = The ground level = 0 m

h₂ = The altitude with which she crosses the bar

∴ 1/2·m·(v² - u²) = m·g·(h₂ - h₁)

(h₂ - h₁) = (v² - u²)/(2·g) = (11² - 1.1²)/(2·9.8) = 6.11173469388

h₂ = 6.11173469388 + h₁ = 6.11173469388 + 0 = 6.11173469388

h₂ = 6.11173469388

Her altitude as she crosses over the bar, h₂ ≈ 6.1 m.

3 0
3 years ago
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