Answer: The half-life of a first-order reaction is, 
Explanation:
All the radioactive reactions follows first order kinetics.
Rate law expression for first order kinetics is given by the equation:
![k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
where,
k = rate constant = ?
t = time taken = 440 s
= initial amount of the reactant = 0.50 M
[A] = left amount = 0.20 M
Putting values in above equation, we get:


The equation used to calculate half life for first order kinetics:

Putting values in this equation, we get:

Therefore, the half-life of a first-order reaction is, 
count the elements in eqn MgI2 + Br2 -> MgBr2 + I2
1 Mg, 2I, 2Br on the left n
1 Mg, 2I, 2Br on the right
they are equal so the eqn is balanced
Answer:
Here's what I get
Explanation:
Ethylamine has an N atom with a lone pair of electrons.
It can act as a Brønsted-Lowry base and accept a proton from water and become an ethylammonium ion.
The structure of the ion is shown below (there is a C atom at each of the four-way bond intersections).
B. Rovers are what you are looking for