Answer:
0.336 J/g/C
Explanation:
Recall the equation for specific heat:
q = mcΔT
1250 = 25 x c x 149
c = 0.336
Answer: Option A) 25mL
Explanation:
Given that,
Original volume of gas (V1) = 75mL
Original temperature of gas (T1) = 450K
New volume V2 = ?
New temperature T2 = 150K
Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law
V1/T1 = V2/T2
75mL/450K = V2/150K
To get the value of T2, cross multiply
75mL x 150K = 450K x V2
11250mL•K = 450K•V2
Divide both sides by 450K
11250mL•K / 450K = 450K•V2/450K
25mL = V2
Thus, the new volume of the gas is 25mL
Answer:
CaF2 + CO3- ----> CaCO3 + 2 F-
Explanation:
The chemical compounds found on the left side of the date are the reagents and those found on the right are the products, where calcium carbonate appears.
Calcium carbonate is a quaternary salt
Answer:
Clastic sedimentary rocks are made up of pieces (clasts) of pre-existing rocks. Pieces of rock are loosened by weathering, then transported to some basin or depression where sediment is trapped. If the sediment is buried deeply, it becomes compacted and cemented, forming sedimentary rock.
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Answer:
Option D
Explanation:
A solution is neutral if it contains equal concentrations of hydronium and hydroxide ions; acidic if it contains a greater concentration of hydronium ions than hydroxide ions; and basic if it contains a lesser concentration of hydronium ions than hydroxide ions.
A common means of expressing quantities, the values of which may span many orders of magnitude, is to use a logarithmic scale.
The hydroxide ion molarity may be expressed as a p-function, or pOH.
pOH = −log[OH−]
Basic solutions are those with hydronium ion molarities less than 1.0 × 10−7 M and hydroxide ion molarities greater than 1.0 × 10−7 M (corresponding to pH values greater than 7.00 and pOH values less than 7.00).
