Answer: 778 ml
Explanation:
To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,
where,
are the initial volume and temperature of the gas.
are the final volume and temperature of the gas.
We are given:
Putting values in above equation, we get:
Thus volume the gas occupy at 30.0°C is 778 ml
<span>Blood pH has an ideal level of about 7.3 to 7.4. It is important for the pH ofblood to remain constant because if your blood pH varies, itcan be deadly.<span>hope this helps </span></span>
Heat can be absorbed or produced
These questions are all about indirect and direct variation with PV=nRT, the ideal gas equation
Q3.
false, because of PV=nRT, the ideal gas equation if V goes up, P has to go down to equal nRT
Q4. false, if V remains constant, and P and T are constant as moles of gas are added, then something is wrong becse something has to change when stuff is added (V has to go down)
Q5.
PV=nRT
when T and n are constant, (R is the gas constant)
PV=k, aka V=k/P which means inversly proportional
TRUE
Q6.
ggeasy
refer to past question
PV=k
if P is doubled then V has to halve in order to equal k
1/2 times 2=1
volume is halved
Q7. use charles law
V/T=k
so
given
V=4
T= kelvins, so 299
4/299=k
so when temp goes to 22 does V go to 3.95
4/299=3.95/295?
true
because they're equal
Q8
FALSE, must be used in kelvins
T=absolute tempurature in kelvins
Q9
PV=nRT
solve for T
(PV)/(nR)=T
use final volumes and pressures
P=5atm
V=24L
n=1
R=0.082057 atm L/(mol K)
(5atm*24L)/(1mol*0.082057 atm L/mol K)=T
see, if you didn't mess up, the units cancel nicely
T=1462.4
1200 K is closest
Q10
PV/T=constant because moles are constant (supposedly)
V=4L
P=2.08atm
T=275K
so find initial to final is constant
(2.08atm*4L)/(275K)=(Pfinal*2.5L)/(323K)
solve for Pfinal
Pfinal=3.92315 atm
answer is 3.9atm
Merry Christmas
<u>Answer:</u>
The mass of the atom depends on the sub atomic particles present in the nucleus of an atom.
That is, the protons and the neutrons.
Electrons are present around the nucleus and the mass is negligible since its mass is very very less.
<em>mass of a proton = 
</em>
<em>mass of a neutron = 
</em>
<em>mass of an electron = 
</em>
Mass number represents the mass of one particular isotope and it is a whole number for example, 
Mass number is 13 and atomic number is 6 for the carbon isotope C-13.
Atomic mass is different from mass number and it is a fraction since it is the average atomic mass of all the isotopes of an atom.
Atomic mass of C is 12.011 amu which we see in the periodic table is the average atomic mass of isotopes C-12, C-13 and C-14.
