CaCl2(s) -> Ca^2+(aq)+Cl(aq)
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Answer:</h3>
52 g water
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Explanation:</h3>
In this question we are given;
Amount of heat, Q = 520 calories
Change in temperature, K = 10 K
We are required to calculate the mass of water.
Amount of heat is calculated by multiplying mass by specific heat capacity by change in temperature.
Q = m × c × Δt
The specific heat capacity,c of water = 1 Cal/g°C or 4.184 J/g°C
Rearranging the formula;
m = Q ÷ cΔt
= 520 Cal ÷ (1 Cal/g°C×10 K)
= 52 g
Thus, the mass of water sample is 52 g
Answer:
32 yd
Explanation:
hope this helps :) A P E X
35.453 (chlorine) + 10.811 (boron) = 46.264