Ethane
see the picture for explanation
Answer:
Let x equal the percentage abundance of one of the two isotopes. The other isotope must then have an abundance of 100 percent minus x percent, which you express in decimal form as (1 - x). For nitrogen, you can set x equal to the abundance of N14 and (1 - x) as the abundance of N15.
Explanation:
Answer 12.2g is the answer
Balanced chemical equation is
3CaCl2 +2Na3PO4-->6NaCl +Ca3(PO4)2
moles of CaCl2 =89.3g/[ (35.5x2) +40]=0.805moles
from the equation above the ratio of CaCl2 to Ca3(PO4)2 is 3:1 therefore the moles of Ca3(PO4)2 is 0.809/3=0.268moles
mass is therefore 0.268 x310.18(R.F.M of Ca3(PO4)2 ) =83.23grams
<span>Given mass: 3.810 g of h2o and 13.96 g of co2.
Mass of CO2 : 13.96 g
moles of CO2 : 0.317 moles / 44.0098
moles of C : 0.317 moles
Mass of water = 3.81 g
moles of water = 0.212 moles / 18.015
moles of H = 0.423 moles X2
Hence the molar ratio C : H is 0.317 : 0.423
= 1.000 : 1.334
Multiplying by 3 on both ratios we get: 3.000 : 4.003
Therefore the empirical formula is C3H4</span>