Question

What would be the volume in liters of an 2.45 liter sample of gas at 594 °C

Answer 1

Answer:

$V_2= 1.19L$

Explanation:

Hello there!

In this case, since the STP conditions are defined by 1 atm (101.3 kPa) and 273 K, it is possible for us to use the combined gas law for this problem as we are given variable pressure, temperature and volume:

$\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}$

In such a way, solving for V2 as the final volume, we obtain:

$V_2=\frac{P_1V_1T_2}{P_2T_1} =\frac{156kPa*2.45L*273.15K}{101.3kPa*(594+273)K}\\\\V_2= 1.19L$

Regards!