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shtirl [24]
2 years ago
15

What is the pH of a solution made by diluting 1.00 mL of 0.10 M HCl with enough distilled water to make 1.00 L of solution?

Chemistry
1 answer:
yKpoI14uk [10]2 years ago
3 0

Answer:

The answer to your question is  pH = 4

Explanation:

Data

Volume 1 = V1 = 1 ml = 0.001 l

Concentration 1 = C1 = 0.1 M

Volume 2 = V2 = 1 l

Concentration 2 = C2 = ?

Process

1.- Find the new concentration of the solution

                    C₁V₂  = C₂V₂

Solve for C₂

                     C₂ = C₁V₁ / V₂

Substitution

                     C₂ = (0.1 x 0.001) / 1

Result

                     C₂ = 0.0001 M

2.- Find the pH of the solution

Formula

                pH = -log[H⁺]

Substitution

                pH = - log[0.0001]

Simplification

                pH = 4                  

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Answer:

Explanation:

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The oxidation number of K in KClO₂:

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                                K + (-1) = 0

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The oxidation number Cl in KClO₂ is -1

For Cl in KCl, the oxidation number is -1

For O in KClO₂, the oxidation number is (2 x -2) = -4

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K moves from an oxidation state of +5 to +1. This is a gain of electrons and K has undergone reduction. We then say K is reduced.

O moves from an oxidation state of -4 to 0. This is a loss of electrons and O has undergone oxidation. We say O is oxidized.

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