How many moles are present in 2. 45 x 1023 molecules of ch4.
1 answer:
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<u>Answer:</u> For the given amount of sweat lost, the amount of energy required will be 692,899 Joules.
<u>Explanation:</u>
We are given:
Heat of vaporization for water = 2257 J/g
Amount of sweat lost = 307 grams
Applying unitary method:
For 1 g of sweat lost, the energy required is 2257 Joules
So, for 307 grams of sweat lost, the energy required will be =
Hence, for the given amount of sweat lost, the amount of energy required will be 692,899 Joules.