Answer: 14mL
Explanation:
From the question, we've been told that the that the density of Hg(l) at 0°C is about 14 g mL-1.
14g = 1mL
We should note that atomic weight of mercury = 200.59.
Therefore, 1 mol Hg = 200.59 g
Therefore, the answer that is closest to the volume of one mole of Hg(l) at this temperature will be:
= 200.59/14
= 14.3 mL
= 14mL approximately
Answer:
2 the mass is greater than 10.0gram
Explanation:
2 the mass is greater than 10.0gram
Answer:
a. Xm = 0.0229
b. 0.0234 moles
c. 354.1 g/mol
Explanation:
ΔP = P° . Xm
ΔP = P° - P', where P° is vapor pressure of pure solvent and P', vapor pressure of solution-
This is the formula for lowering vapor pressure.
If we apply the data given: 523 Torr - 511 Torr = 523 . Xm
Xm = ( 523 Torr - 511 Torr) / 523 Torr → 0.0229
Xm = Mole fraction of solute → Moles of solute / Total moles (sv + solute)
We can make this equation to determine moles of solute
0.0229 = Moles of solute / Moles of solute + 1
0.0229 (Moles of solute + 1) = Moles of solute
0.0229 = Moles of solute - 0.0229 moles of solute
0.0229 = 0.9771 moles of solute → 0.0229 / 0.9971 = 0.0234 moles
Molecular mass of solute → g/mol → 8.3 g / 0.0234 mol = 354.1 g/mol
Kidneys<span> filter the extra water and toxic materials in your blood (circulatory </span>system<span>). The help </span>maintain homeostasis<span> by keeping the level of toxic materials down in your</span>body<span>. The filtered materials are sent, with the extra water, to your bladder , where it is known as urine/ pee.</span>
The most abundant isotope is Gz-83 because the average atomic mass of Gz is closer to 83.
The average atomic mass is defined as the weigthed mean of the isotopes.
The mass of the isotopes is 80, 81 and 83 uma, respectively.
As the average atomic mass (82.74uma) is closer to the atomic mass of Gz-83 than the mass of the other isotopes, you can interpretate that the most abundant isotope is Gz-83.
Learn more about average atomic mass in:
brainly.com/question/21536220
