<span>Silver oxalate dissociation equation is following:
</span><span>
Ag</span>₂C₂O₄(s) ⇄ 2Ag⁺(aq) + C₂O₄²⁻(aq)
According to reaction follows next stoichiometric ratio:
[Ag⁺] : [C₂O₄²⁻] = 2 : 1
[C₂O₄²⁻] = [Ag⁺] / 2
[C₂O₄²⁻] = (1.7×10⁻⁴)/2 = 8.5×10⁻⁵ M
So, solubility product constants for silver oxalate is:
Ksp = [Ag⁺]² x [C₂O₄²⁻]
Ksp = [1.7×10⁻⁴]² x [8.5×10⁻⁵]
Ksp = 2.46×10⁻¹²
Answer:
2 HCl + CaCO3 = CaCl2 + H2O + CO2
Explanation:
On the right side we have 2xCl, to get the same amount we will multiply HCl on the left side by 2.
This will give us 2xH on the left side; we also have 2xH on the right side ( in H2O).
On both sides we have 1x Ca; 1x C.
On the left side we have 3XO (in CaCO3), on the right side we have 1O in H20 and 2xO in CO2, so 3x O on the right side as well.
The reaction is balanced.
Answer: 17.9 g
Explanation:
1) Chemical equation:
H₂ (g) + Cl₂ (g) → 2HCl (g)
2) mole ratios:
1 mol H₂ : 1 mol Cl₂ : 2 mol HCl
3) Since, the pressure and temperature conditions do not change, the same proportion is valid for the volumes. Then:
1 liter H₂ / 2 liter HCl = 5.15 liter H₂ / x
⇒ x = 5.5 × 2 / 1 = 11 liter HCl
4) Calculate the number of moles of HCl in 11 liter of HCl at STP
At STP, 1 mol of gas = 22.4 liter
⇒ 11 liter × 1mol / 22.4 liter = 0.491 mol HCl
5) Use the molar mass to convert 0.491 mol to grams
molar mass of HCl = 1.008 g/mol + 35.453 g/mol = 36.461 g/mol
mass in grams = nuumber of moles × molar mass = 36.461 g/mol × 0.491 mol = 17.90 g.
