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3 years ago

What are three limitations of current cloaking technology.

Chemistry

1 answer:

kirill [66]3 years ago

4 0

Explanation:

1.undetectable to electromagnetic waves

2.hiding an object from an illumination containing diffre t wave lengths become difficult as the object sizes grow.

3. reduce the scattering by two orders.

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Type the formula of the following compound: Aluminum nitride

evablogger [386]

The formula for that compound is AlN

6 0

3 years ago

a scuba diver's tank contains 0.29g of oxygen compressed into volume of 2.3L. What is the pressure in the tank at 9C?

viva [34]

Answer:

The answer to your question is P = 0.18 atm

Explanation:

Data

mass of O₂ = 0.29 g

Volume = 2.3 l

Pressure = ?

Temperature = 9°C

constant of ideal gases = 0.082 atm l/mol°K

Process

1.- Convert the mass of O₂ to moles

16 g of O₂ -------------------- 1 mol

0.29 g of O₂ ---------------- x

x = (0.29 x 1)/16

x = 0.29/16

x = 0.018 moles

2.- Convert the temperature to °K

Temperature = 9 + 273 = 282°K

3.- Use the ideal gas law ro find the answer

PV = nRT

-Solve for P

P = nRT/V

-Substitution

P = (0.018 x 0.082 x 282) / 2.3

-Simplification

P = 0.416/2.3

-Result

P = 0.18 atm

5 0

3 years ago

How many electrons can be held in the second orbital

mariarad [96]

Second orbital can hold 8 electrons

3 0

3 years ago

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Why is computational chemistry important?

Tema [17]

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4 0

3 years ago

The CRC Handbook, a large reference book of chemical and physical data, lists two isotopes of indium (). The atomic mass of 4.28

ivanzaharov [21]

Answer: The mass of second isotope of indium is 114.904 amu

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

.....(1)

Let the mass of isotope 2 of indium be 'x'

For isotope 1:

Mass of isotope 1 = 112.904 amu

Percentage abundance of isotope 1 = 4.28 %

Fractional abundance of isotope 1 = 0.0428

For isotope 2:

Mass of isotope 2 = x amu

Percentage abundance of isotope 2 = [100 - 4.28] = 95.72 %

Fractional abundance of isotope 2 = 0.9572

Average atomic mass of indium = 114.818 amu

Putting values in equation 1, we get:

$114.818=[(112.904\times 0.0428)+(x\times 0.9572)]\\\\x=114.904amu$

Hence, the mass of second isotope of indium is 114.904 amu

4 0

3 years ago