NaOH or sodium hydroxide is a base which reacts with HCl or Hydrochloric acid to from a salt and water. The equation that represents this reaction is as follows: NaOH (I) + HCl (l) ==H2O (l) +NaCl (aq). The reaction between an acid and a base always produces a salt and water. In this case the salt is sodium chloride.

4 0

3 years ago

The population of the Earth at the end of 2018 was approximately 7.7 × 10 9 people. Which of the following is the correct way of

stepladder [879]

Answer:

7700000000

Explanation:

so 7.7 x 10 to the power of 9 is in standard form

to put it into a number you just need to times it by 1000000000

however your answer will only have 8 zeros because of the decimal point

5 0

3 years ago

For the reaction H2PO4- HAsO4 2-HPO4 2-+H2AsO4- <br> what species are a conjugate acid-base pair?

aleksklad [387]

Ionic equation:

$\text{H}_2\text{PO}_4^{-} + \text{HAsO}_4^{2-} \to \text{HPO}_4^{2-} + \text{H}_2\text{AsO}_4^{-}$

The acid and base in a conjugate pair differ by only one proton $\text{H}^{+}$ . The acid loses one proton to produce a conjugate base, whereas the base gains a proton to produce its conjugate acid.

$\text{H}_2\text{PO}_4^{-}$ loses one proton to produce $\text{HPO}_4^{2-}$ in this reaction.

$\text{H}_2\text{PO}_4^{-} \to \text{H}^{+} + \text{HPO}_4^{2-}$

Meanwhile, $\text{HAsO}_4^{2-}$ gains one proton to form $\text{H}_2\text{AsO}_4^{-}$ .

$\text{HAsO}_4^{2-} + \text{H}^{+} \to \text{H}_2\text{AsO}_4^{-}$

Therefore

$\text{H}_2\text{PO}_4^{-}$ is the conjugate acid $\text{HPO}_4^{2-}$ , its conjugate base.
$\text{HAsO}_4^{2-}$ is the conjugate base of $\text{H}_2\text{AsO}_4^{-}$ , its conjugate acid.

8 0

3 years ago

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