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My name is Ann [436]
3 years ago
15

ASAPwhat is an electron cloud ​

Chemistry
1 answer:
Bad White [126]3 years ago
8 0

Explanation:

An electron cloud is the region of space that surrounds the nucleus of an atom under the nucleus of the negatively charged sub-atomic particles.

  • An atoms is made up of some particles.
  • The proton is positively charged and it is located in the nucleus of an atom.
  • The neutrons do not carry any charges and occupies the nucleus with protons.
  • Electrons are the negatively charged particles outside the nucleus.
  • The electron cloud is portion of an atom with greatest probability of finding an electron.

Learn more:

Electron cloud brainly.com/question/1832385

#learnwithBrainly

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Calculate the freezing point (in degrees C) of a solution made by dissolving 7.99 g of anthracene{C14H10} in 79 g of benzene. Th
mario62 [17]

<u>Answer:</u> The freezing point of solution is 2.6°C

<u>Explanation:</u>

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

where,

\Delta T_f = \text{Freezing point of pure solution}-\text{Freezing point of solution}

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_f = molal freezing point depression constant = 5.12 K/m  = 5.12 °C/m

m_{solute} = Given mass of solute (anthracene) = 7.99 g

M_{solute} = Molar mass of solute (anthracene) = 178.23  g/mol

W_{solvent} = Mass of solvent (benzene) = 79 g

Putting values in above equation, we get:

5.5-\text{Freezing point of solution}=1\times 5.12^oC/m\times \frac{7.99\times 1000}{178.23g/mol\times 79}\\\\\text{Freezing point of solution}=2.6^oC

Hence, the freezing point of solution is 2.6°C

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