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Nesterboy [21]
3 years ago
7

Members of which group easily lose an electron to form a +1 cation? halogens alkaline earth metals noble gases alkali metals

Chemistry
2 answers:
sp2606 [1]3 years ago
7 0

I think the correct answer from the choices listed above is option D. Members of the alkali metals easily lose an electron to form a +1 cation. The halogens represents element like F, Cl which easily gain an electron. Alkaline earth metals represents element like Mg, Ca which easily lose two electrons.

Kryger [21]3 years ago
5 0

Answer:

D. Members of the alkali metals easily lose an electron to form a +1 cation. The halogens represents element like F, Cl which easily gain an electron. Alkaline earth metals represents element like Mg, Ca which easily lose two electrons.

Explanation:

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3 years ago
A chemist dissolves of pure potassium hydroxide in enough water to make up of solution. Calculate the pH of the solution. (The t
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Answer:

12.99

Explanation:

<em>A chemist dissolves 716. mg of pure potassium hydroxide in enough water to make up 130. mL of solution. Calculate the pH of the solution. (The temperature of the solution is 25 °C.) Be sure your answer has the correct number of significant digits.</em>

Step 1: Given data

  • Mass of KOH: 716. mg (0.716 g)
  • Volume of the solution: 130. mL (0.130 L)

Step 2: Calculate the moles corresponding to 0.716 g of KOH

The molar mass of KOH is 56.11 g/mol.

0.716 g × 1 mol/56.11 g = 0.0128 mol

Step 3: Calculate the molar concentration of KOH

[KOH] = 0.0128 mol/0.130 L = 0.0985 M

Step 4: Write the ionization reaction of KOH

KOH(aq) ⇒ K⁺(aq) + OH⁻(aq)

The molar ratio of KOH to OH⁻is 1:1. Then, [OH⁻] = 0.0985 M

Step 5: Calculate the pOH

We will use the following expression.

pOH = -log [OH⁻] = -log 0.0985 = 1.01

Step 6: Calculate the pH

We will use the following expression.

pH + pOH = 14

pH = 14 - pOH = 14 -1.01 = 12.99

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