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Svetradugi [14.3K]
3 years ago
15

A wheel with a weight of 388 N comes off a moving truck and rolls without slipping along a highway. At the bottom of a hill it i

s rotating at an angular velocity of 23.6 rad/s . The radius of the wheel is 0.591 m and its moment of inertia about its rotation axis is 0.800 MR2. Friction does work on the wheel as it rolls up the hill to a stop, at a height of h above the bottom of the hill; this work has a magnitude of 3482 J .
Calculate h. Use 9.81m/s2 for the acceleration due to gravity.
Physics
1 answer:
Alisiya [41]3 years ago
4 0

the correct answer is 14m

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Relate the output of energy from a heat engine to the energy put into the heat engine considering the second law of thermodynami
Vinil7 [7]

<u>Answer: </u>

<em>Considering the II law of thermodynamics</em>

<em>From the figure</em>

<em>Out put of energy: </em>

Heat supplied from the source/ reservoir  (Q₁) - Heat rejected to the surroundings from the system (Q) = Q₁ - Q₂. Also known as Net work done on the system.

<em>Input of energy: </em>

Amount of heat energy supplied to the system from the source (Q₁ ).

Efficiency (H.E) = η = Output÷ Input

                             η  = (Q₁ - Q₂) ÷ Q₁

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3 0
3 years ago
You illuminate a slit with a width of 70.3 μm with a light of wavelength 719 nm and observe the resulting diffraction pattern on
Zielflug [23.3K]

Answer:

4.3 cm

Explanation:

We are given that

Width,d=70.3\mu m=70.3\times10^{-6} m

1\mu m=10^{-6} m

Wavelength,\lambda=719 nm=719\times 10^{-9} m

1nm=10^{-9} m

r=2.11 m

We have to find the width in cm of the pattern.

The angle for the first minimum m=1

sin\theta_{min}\approx \theta=\frac{\lambda}{d}=\frac{719\times 10^{-9}}{70.3\times 10^{-6}}=0.0102 rad

y=r\theta=2.11\times 0.0102=0.0215 m

The width of the pattern=2y=2\times 0.0215=0.043 m=0.043\times 100=4.3 cm

8 0
3 years ago
Bismuth-210 has a half-life of 5 days. If you
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Answer:

A = 62.5 g

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6 0
4 years ago
If an oscillating mass has a frequency of 1.25 Hz, it makes 100 oscillations in
KatRina [158]

Answer:

Time, t = 80 seconds

Explanation:

Given that,

The frequency of the oscillating mass, f = 1.25 Hz

Number of oscillations, n = 100

We need to find the time in which it makes 100 oscillations. We know that the frequency of an object is number of oscillations per unit time. It is given by :

f=\dfrac{n}{t}

t=\dfrac{n}{f}

t=\dfrac{100}{1.25\ Hz}

t = 80 seconds

So, it will make 100 oscillations in 80 seconds. Hence, this is the required solution.

4 0
3 years ago
How much work does it take to lift a 1000 kg elephant into a truck bed that is 1 meter of the ground? (answer in joules)
nadezda [96]
It would be a lot of work
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3 years ago
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