<u>Answer: </u>
<em>Considering the II law of thermodynamics</em>
<em>From the figure</em>
<em>Out put of energy: </em>
Heat supplied from the source/ reservoir (Q₁) - Heat rejected to the surroundings from the system (Q) = Q₁ - Q₂. Also known as Net work done on the system.
<em>Input of energy: </em>
Amount of heat energy supplied to the system from the source (Q₁ ).
Efficiency (H.E) = η = Output÷ Input
η = (Q₁ - Q₂) ÷ Q₁
OR η = Wnet ÷ Q₁ ; since Wnet = (Q₁ - Q₂)
Answer:
4.3 cm
Explanation:
We are given that
Width,d=70.3

Wavelength,


We have to find the width in cm of the pattern.
The angle for the first minimum m=1


The width of the pattern=
Answer:
A = 62.5 g
using half life formulas, plug in missing variables.
Answer:
Time, t = 80 seconds
Explanation:
Given that,
The frequency of the oscillating mass, f = 1.25 Hz
Number of oscillations, n = 100
We need to find the time in which it makes 100 oscillations. We know that the frequency of an object is number of oscillations per unit time. It is given by :



t = 80 seconds
So, it will make 100 oscillations in 80 seconds. Hence, this is the required solution.