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mina [271]
3 years ago
6

A baseball pitcher throws a baseball horizontally at a linear speed of 42.5 m/s (about 95 mi/h). Before being caught, the baseba

ll travels a horizontal distance of 16.5 m and rotates through an angle of 49.0 rad. The baseball has a radius of 3.67 cm and is rotating about an axis as it travels, much like the earth does. What is the tangential speed of a point on the "equator" of the baseball?
Physics
1 answer:
Marina CMI [18]3 years ago
5 0

Answer:

4.5m/s

Explanation:

Linear speed (v) = 42.5m/s

Distance(x) = 16.5m

θ= 49.0 rad

radius (r) = 3.67 cm

= 0.0367m

The time taken to travel = t

Recall that speed = distance / time

Time = distance / speed

t = x/v

t = 16.5/42.5

t = 0.4 secs

tangential velocity is proportional to the radius and angular velocity ω

Vt = rω

Angular velocity (ω) = θ/t

ω = 49/0.4

ω = 122.5 rad/s

Vt = rω

Vt = 0.0367 * 122.5

Vt =4.5 m/s

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A stalled car is being pushed up a hill at constant velocity by three people. The net force on the car is Group of answer choice
vfiekz [6]

Answer:

Zero

Explanation:

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

Mathematically, net force is given by the formula;

Fnet = Fapp + Fg

Where;

Fnet is the net force.

Fapp is the applied force.

Fg is the force due to gravitation.

In this scenario, a stalled car is being pushed up a hill at constant velocity by three people. Thus, the net force on the car is zero because all the forces acting on any physical object is equal to zero and represents a constant velocity; by balancing or cancelling each other out.

According to Sir Isaac Newton's First Law of Motion which is known as Law of Inertia, it states that an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.

7 0
3 years ago
Analyze the data to identify the mathematical relationship between the
koban [17]

Answer:

C.) Wave B has about 2.25 times more energy than wave A

Explanation:

5 0
3 years ago
Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The
Greeley [361]

Answer:

I = 215.76 A  

Explanation:

The direction of magnetic field produced by conductor 1 on the location of conductor 2 is towards left. Based on Right Hand Rule -1 and taking figure 21.3 as reference, the direction of force Fm due to magnetic field produced at C_2 is shown above. The force Fm balances the weight of conductor 2.  

Fm = u_o*I^2*L/2*π*d

where I is the current in each rod, d = 0.0082 m is the distance 27rId  

between each, L = 0.85 m is the length of each rod.

Fm = 4π*10^-7*I^2*1.1/2*π*0.0083

The mass of each rod is m = 0.0276 kg  

F_m = mg

4π*10^-7*I^2*1.1/2*π*0.0083=0.0276*9.8

I = 215.76 A  

note:

mathematical calculation maybe wrong or having little bit error but the method is perfectly fine

5 0
3 years ago
The base of a hexagonal prism has an apothem measuring 10 inches and an area of 346.41 square inches. the prism is 12 inches tal
tigry1 [53]

The approximate lateral area of the prism is determined as 831 square inches.

<h3>What is lateral area of the hexagonal prism?</h3>

The lateral area of the hexagonal prism is calculated as follows;

LA = PH

where;

  • P is perimeter of the prism
  • H is height

A = ¹/₂Pa

where;

  • a is apothem = 10 inches
  • A is base area = 346.41 in²

346.41 = ¹/₂(10)P

346.41 = 5P

P = 346.41/5

P = 69.282 inches

LA = PH

LA = 69.282 x 12

LA = 831.38 in²

Learn more about lateral area of prism here: brainly.com/question/296674

#SPJ4

8 0
2 years ago
Peter’s body supplies a force of 500 N to run up a 10-m hill in 10 s. How much power is involved in Peter’s run up the hill? Exp
shutvik [7]

Answer: 500 Watts

Explanation:

Power P is the speed with which work W is done. Its unit is Watts (W), being 1 W=\frac{1 Joule}{1 s}.

Power is mathematically expressed as:

P=\frac{W}{t} (1)

Where t is the time during which work W  is performed.

On the other hand, the Work W done by a Force F refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.  It is a scalar magnitude, and its unit in the International System of Units is the Joule (like energy). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter (1J=(1N)(1m)=Nm  ).

When the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:  

W=(F)(d) (2)

In this case, we have the following data:

F=500 N

d=10 m

t=10 s

So, let's calculate the work done by Peter and then find how much power is involved:

From (2):

W=(500 N)(10 m) (3)

W=5000 J (4)

Substituting (4) in (1):

P=\frac{5000 J}{10 s} (5)

Finally:

P=500 W

3 0
3 years ago
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