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AlexFokin [52]
3 years ago
10

A child standing on a bus remains still when the bus is at rest. When the bus moves forward and then slows down, the child conti

nues moving forward at the original speed. This is an example of
A. Newton's Third Law of Motion.
B. Newton's First Law of Motion.
C. an action-reaction pair.
D. Newton's Second Law of Motion
Physics
2 answers:
pochemuha3 years ago
4 0
B. Newton's First Law, I'm pretty sure. The first states that an object in motion stays in motion, and an object at rest stays at rest until an outside force is applied, and that seems pretty relevant.
Scilla [17]3 years ago
4 0
Newtons First Law of Motion. I just took the Test.
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V=xf-xi/t solve for t
irina [24]

Answer:

t=\frac{x_f-x_i}{v}

Explanation:

Starting from the equation:

v=\frac{x_f-x_i}{t}

First of all, let's multiply by t on both sides:

v\cdot t = \frac{x_f-x_i}{t}\cdot t \\vt = x_f - x_i

And then, let's divide by v on both sides:

\frac{vt}{v}=\frac{x_f-x_i}{v}\\t=\frac{x_f-x_i}{v}

So, finally

t=\frac{x_f-x_i}{v}

7 0
3 years ago
A large lightning bolt consists of a 18.2~\text{kA}18.2 kA current that moved 30.0~\text{C}30.0 C of charge. Assuming a constant
marissa [1.9K]

Answer:

1.65\times {-3} \text { s}

Explanation:

Current is the rate of flow of charge.

I=\dfrac{Q}{t}

t = \dfrac{Q}{I}

t = \dfrac{30.0}{18.2\times10^3} =1.65\times {0-3} = 1.65\times {-3} \text { s}

6 0
3 years ago
Read 2 more answers
Why is vehicle systems forensics useful today? Cars are less computerized than before More people own cars Devices like smartpho
kvasek [131]

Answer:

Devices like smartphones can interface with cars and leave evidence

Explanation:

Vehicle system forensic relates to digital data stored in a vehicles system.

Bluetooth connection times can be used to figure out at what time the owner was near his car. e.g. between a smart-watch and car infotainment system

6 0
3 years ago
The kinetic energy of a rocket is increased by a factor of eight after its engines are fired, whereas its total mass is reduced
Rudik [331]

The momentum increases by a factor of 2

Explanation:

We can solve this problem by rewriting the momentum of the rocket in terms of the kinetic energy and the mass.

The kinetic energy of the rocket is:

K=\frac{1}{2}mv^2 (1)

where

m is the mass

v is the velocity

The momentum of the rocket is

p=mv (2)

From eq.(1) we get

v=\sqrt{\frac{2K}{m}}

and substituting into (2),

p=\sqrt{2mK}

Now in this problem we have:

- The kinetic energy of the rocket is increased by a factor 8:

K' = 8K

- The mass is reduced by half:

m'=\frac{m}{2}

Substituting, we find the new momentum:

p'=\sqrt{2(\frac{m}{2}(8K)}=\sqrt{4(2mK)}=2\sqrt{2mK}=2p

So, the momentum increases by a factor of 2.

Learn more about momentum and kinetic energy:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

brainly.com/question/6536722

#LearnwithBrainly

4 0
3 years ago
A uniform plank of length 5.0 m and weight 225 N rests horizontally on two supports, with 1.1 m of the plank hanging over the ri
lawyer [7]

Answer:

x = 0.6034 m

Explanation:

Given

L = 5 m

Wplank = 225 N

Wman = 522 N

d = 1.1 m

x = ?

We have to take sum of torques about the right support point.  If the board is just about to tip, the normal force from the left support will be going to zero.  So the only torques come from the weight of the plank and the weight of the man.

∑τ = 0  ⇒     τ₁ + τ₂ = 0  

Torque come from the weight of the plank = τ₁

Torque come from the weight of the man = τ₂

⇒  τ₁ = + (5 - 1.1)*(225/5)*((5 - 1.1)/2) - (1.1)*(225/5)*((1.1)/2) = 315 N-m (counterclockwise)

⇒  τ₂ = Wman*x = 522 N*x   (clockwise)

then

τ₁ + τ₂ = (315 N-m) + (- 522 N*x) = 0

⇒  x = 0.6034 m

7 0
3 years ago
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