Answer:
Q = 47.06 degrees
Explanation:
Given:
- The transmitted intensity I = 0.464 I_o
- Incident Intensity I = I_o
Find:
What angle should the principle axis make with respect to the incident polarization
Solution:
- The relation of transmitted Intensity I to to the incident intensity I_o on a plane paper with its principle axis is given by:
I = I_o * cos^2 (Q)
- Where Q is the angle between the Incident polarized Light and its angle with the principle axis. Hence, Using the relation given above:
Q = cos ^-1 (sqrt (I / I_o))
- Plug the values in:
Q = cos^-1 ( sqrt (0.464))
Q = cos^-1 (0.6811754546)
Q = 47.06 degrees
Explanation:
Terminal velocity is given by:
Here, m is the mass of the falling object, g is the gravitational acceleration, is the drag coefficient, is the fluid density through which the object is falling, and A is the projected area of the object. in this case the projected area is given by:
Recall that drag coefficient for a horizontal skydiver is equal to 1 and air density is .
Without drag contribution the motion of the person is an uniformly accelerated motion, thus:
Answer:
The coefficient is 0.90
Explanation:
Drawing a diagram makes thing easier, we will assume that the acceleration tends to zero because it start barely moving.
Explanation:
I think it will increase a little bit ... just image ... if the temperature is 0, the velocity will be 0 too. because the vibration of atom is so weak and the sound cant progation.
But even more pain on pain and then pain and pain ya feel me and even more pain okay and yes more pain