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Airida [17]
3 years ago
7

The following are steps involved in transmission at the cholinergic synapse:

Physics
1 answer:
Westkost [7]3 years ago
6 0

Answer:

3. Step 1; An action potential depolarizes the axon terminal at the presynaptic membrane

2. Step 2; Calcium ions enter the axon terminal

4. Step 3; Acetylcholine is released from storage vesicles by exocytosis

5. Step 4; Acetylcholine binds to receptors on the postsynaptic membrane

1. Step 5; Chemically gated ion channels on the postsynaptic membrane are opened

Explanation:

3. The cholinergic synapse starts at the point of arrival of an electrochemical impulse or action potentials at the synaptic knob of the axon terminal of a presynaptic neuron membrane

2. The arrival of the action potential at the axon terminal causes the calcium ion Ca²⁺ channels to open and Ca²⁺ enters into the synaptic knob, resulting in the fusion of the presynaptic membrane and synaptic vesicles

4. The fusion enables the release into the synaptic cleft of many acetylcholine (ACh) transmitter molecules by exocytosis

5. Some of the ACh are transported across the synaptic cleft and bind to postsynaptic neuron membrane embedded ACh receptors

1. The binding of the ACh neurotransmitter molecules to receptors on the membrane of the dendrites of a neuron it leads to the opening of ion channels

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3 years ago
The sun is 150,000,000 km from the earth.
aniked [119]

Answer:

<h3>What is the angular speed of the earth around the sun? </h3>

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7.2921159 × 10 {}^{ - 5}  \:  \:  \frac{radians}{second}

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3 years ago
A spherical ball of charged particles has a uniform charge density. In terms of the ball's radius R, at what radial distances in
eimsori [14]

Answer:

Electric field at radius r inside the solid sphere is

Electric field at radius r between inner radius and outer radius of the shell is

E=0 N/C

Explanation:Given

The radius of the solid sphere is

The charge on the solid sphere is

The inner radius of the shell is

The outer radius of the shell is

The total charge on the shell is

PART(A)

The magnitude of electric field at radius r where  \\The volumetric charge density of the solid sphere will be

The charge enclosed by the radius r inside the solid sphere is

rho=

According to gauss law

PART(B)

The electric field at radius r where

The shell is conducting so due to induction of charge

The charge induced on the inner surface of the shell is equal in magnitude of the total charge on the solid sphere but polarity will be changed because a conducting shell has no net electric field inside the shell

So,

The charge on the inner surface of the shell is

Due to conservation of the charge on the shell

The charge accumulated on the outer surface of the shell is

The charge enclosed by the radius r where

According to gauss law

Read more on Brainly.com - brainly.com/question/13242041#readmore

3 0
3 years ago
Figure 3 shows a bicycle of mass 15 kg resting in a vertical position, with the front and back
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Explanation:

There are three forces on the bicycle:

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Sum of the moments at P:

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Sum of the moments at Q:

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Sum of the moments at O:

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Answer:

C. It is the result of diffraction

Explanation:

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