Answer:
C. 1.3 mol
Explanation:
PV = nRT
where P is absolute pressure,
V is volume,
n is number of moles,
R is universal gas constant,
and T is absolute temperature.
Given:
P = 121.59 kPa
V = 31 L
T = 360 K
R = 8.3145 L kPa / mol / K
Find: n
n = PV / (RT)
n = (121.59 kPa × 31 L) / (8.3145 L kPa / mol / K × 360 K)
n = (3769.29 L kPa) / (2993.22 L kPa / mol)
n = 1.26 mol
Round to two significant figures, there are 1.3 moles of gas.
Answer:
(B) 2AgCl + sunlight → Cl2 + 2Ag (decomposition reaction) is correct option.
Answer:
Empirical formula is C₂H₆O
Explanation:
Given data:
Percentage of hydrogen =100 - 86.87% = 13.13%
Percentage of carbon = 52.14%
Percentage of oxygen = 34.73%
Empirical formula = ?
Solution:
Number of gram atoms of H = 13.13 / 1.01 = 13
Number of gram atoms of O = 34.73 / 16 = 2.17
Number of gram atoms of C = 52.14 / 12 = 4.345
Atomic ratio:
C : H : O
4.345/2.17 : 13/2.17 : 2.17/2.17
2 : 6 : 1
C : H : O = 2 : 6 : 1
Empirical formula is C₂H₆O.
Answer:
Following are the responses to the given question:
Explanation:
In many analyses, the homogenous sample with only a particular identity group is desired. Units were picked here depending on their similar characteristics so because research is specifically interested in these qualities. The downside of a homogeneous sample is nevertheless that the exterior validity of a study is decreased. In other words, any results obtained could be appropriately widespread to the general population. On either hand, a heterogeneous sample is capable of overcoming this difficulty, because its diversity is the typical pattern of any sort of sample distortion inside the broader population.
