Answer:
Molality = 0.33 mol/Kg
Explanation:
Given data:
Volume of solvent = 2.00 L
Mass of solute = 225 g
Molality of solution = ?
Solution:
Formula:
Molality = Number of moles of solute / kg of solvent
Now we will calculate the moles of solute.
Number of moles = mass/ molar mass
Number of moles = 225 g/ 342.3 g/mol
Number of moles = 0.66 mol
Now we will calculate the Kg of solvent.
1 L = 1 Kg
2 L = 2 Kg
Molality = Number of moles of solute / kg of solvent
Molality = 0.66 mol / 2 kg
Molality = 0.33 mol/Kg
Answer:
1. KBr
2. 2NH4OH
3. 2NO3
Explanation:
You just need to work backwords and take them step by step.
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4.79 x 10⁻⁷moldm⁻³
Explanation:
Given parameters:
pOH of RbOH = 6.32
Unknown:
Molarity of the base = ?
Solution:
The pH or pOH scale is used for expressing the level of acidity alkalinity of aqueous solutions.
pOH = -log[OH⁻]
we know the pOH to be 6.32
6.32 = -log[OH⁻]
[OH⁻] = inverse log₁₀(6.32)
[OH⁻] = 4.79 x 10⁻⁷moldm⁻³
Learn more:
pH brainly.com/question/12985875
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Answer: The differences is Air masses cover over thousands and hundreds and millions of square kilo. A front is a boundary which two air masses but different temperature and moisture content meet.
Explanation:
Answer:
Heres a picture of the periodic table.
Explanation:
Source(s):Science News for Students