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AnnZ [28]
3 years ago
11

Which example illustrates public scientific communication?

Chemistry
1 answer:
White raven [17]3 years ago
8 0

Answer:

D. A federal government agency publishes an article in a professional scientific journal detailing technical details of a  new virus.

Explanation:

Public scientific communication is a way used by scientists to make the audience able to understand the basics of science to communicate an informed decision. There are several skills under public scientific communication that include connect with the public, talk to journalists, make science understandable, and understand the audience.

<u>The best way to connect with the audience is to publish an article in a professional scientific journal because mostly journals are peer-reviewed having standard of quality.</u>

A federal government agency informing about a  new virus through an article in a professional scientific journal is the best way of public scientific communication as it will be for a specific audience along with a standard of quality.

Hence, the correct answer is "D".

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How to solve a balanced equation
geniusboy [140]

Explanation:

To balance a chemical equation, there are so many approaches to solve the problem.

A balanced chemical equation is one that obeys the law of conservation of matter.

According to this law "matter is neither created nor destroyed by atoms are just rearranged in chemical reaction".

This implies implies that equal number of atoms must be on both sides of the equation.

      There are two main approaches to balancing chemical equation;

  • Inspection
  • mathematical equation

We can inspect the equation and affix the proper coefficients to combining species.

Mathematically, we establish simple solvable algebraic equations to find the number of respective coefficients that will balance the equation:

 For example:

          H₂     +      O₂    →     H₂O

mathematically;

           aH₂     +      bO₂    →     cH₂O

  conserving:

         H :   2a  =  2c

         O:    2b  = c

 let a = 1

      c = 1

      b = \frac{1}{2}

multiply by 2 to give;

   a = 2, b = 1 , c= 2

               2H₂     +      O₂    →     2H₂O

learn more:

Balanced equation brainly.com/question/9325293

#learnwithBrainly

 

7 0
3 years ago
A temperature of –25°C is equivalent to: Question 2 options: 25 K. 248 K. –25 K. 298 K.\
babunello [35]
First, to convert from C to K, add (C+273)=k
So -25+273=248
6 0
3 years ago
Cellulose,the main substance that makes up the
Tema [17]
Cellulose makes up the cell wall

7 0
3 years ago
Read 2 more answers
If the input force applied to one end of a first-class lever is 8 N, and the fulcrum is located 6 m away from the input force bu
MatroZZZ [7]

Answer:

16 N

Explanation:

The ratio of output force to the input force is called mechanical advantage of the lever. Also, the ratio of input arm distance to the output arm distance is called mechanical advantage of the lever.

We have,

Input force = 8 N

Input arm distance = 6 m

Output arm distance = 3 m

We need to find the resulting output force. So,

\dfrac{F_o}{8}=\dfrac{6}{3}\\\\F_o=16\ N

So, the resulting output force is 16 N.

4 0
3 years ago
A room is a cube that measures 4 meters in each dimension. If the temperature changes from 10 C to 30 C, and the pressure decrea
Katen [24]

Answer:

More air will enter the room since the volume of the room increases.

Explanation:

We'll begin by calculating the initial volume (V₁) of the room. This can be obtained as follow

Length (L) of room = 4 m

Initial volume (V₁) =..?

V₁ = L³

V₁ = 4³

V₁ = 64 m³

Next, we shall determine if there is an increase in the volume of the room or not. This can be obtained as follow:

Data obtained from the question include:

Initial volume (V₁) = 64 m³

Initial temperature (T₁) = 10 °C + 273 = 283 K

Final temperature (T₂) = 30 °C + 373 = 303 K

Initial pressure (P₁) = 760 mmHg

Final pressure (P₂) = 718 mmHg

Final volume (V₂) =?

P₁V₁/T₁ = P₂V₂/T₂

760 × 64 / 283 = 718 × V₂ / 303

48640 / 283 = 718 × V₂ / 303

Cross multiply

283 × 718 × V₂ = 48640 × 303

203194 × V₂ = 14737920

Divide both side by 203194

V₂ = 14737920 / 203194

V₂ = 72.53 m³

SUMMARY

Initial volume (V₁) of room = 64 m³

Final volume (V₂) of room = 72.53 m³

From the calculations made above, we can see that the volume of the room increases from 64 m³ to 72.53 m³. Thus more air will enter the room since the volume of the room increases.

6 0
3 years ago
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