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3 years ago

7. A small stone added to boiling liquids to make them boil more evenly without sudden violent releases of

Chemistry

2 answers:

Rzqust [24]3 years ago

8 0

Answer:

A boiling chip, boiling stone, porous bit or anti-bumping granule is a tiny, unevenly shaped piece of substance added to liquids to make them boil more calmly.

These help in making the liquid boil more easily

bixtya [17]3 years ago

7 0

Answer:

umm i think it's called boiling chip

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when 0.863 mol acetone is dissolved in 500 g benzene, the freezing point of benzene drops 8.84°C. what is the molal freezing poi

sveticcg [70]

Answer:

Kf = 5.12 °C/m

Explanation:

1) Data:

a) Solute: acetone

b) Solvent: benzene

c) n (solute) = 0.863 mol

d) mass of solvent = 500 g = 0.500 Kg

e) ΔTf = 8.84 °C

f) Kf = ?

2) Formulae:

Depression of freezing point: ΔTf = m . Kf

Molality: m = n (solute) / kg solvent

3) Solution:

a) m = 0.863 mol / 0.500 kg = 1.726 m

b) Kf = ΔTf / m = 8.84°C / 1.726 m = 5.12 °C/m ← answer

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3 years ago

1. Stan walk 15 km west to the grocery store he shops then walk back 20km east to his house what distance did he cover what was

vitfil [10]

Answer:

His displacement is 0 km because he ends his walk where he started. The total distance of his walk is 20 km because he walks 10 km to the store + 10km back home.

Explanation:

Hope this helps:)

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3 years ago

A 25.00 ml sample of hbr is titrated with a 0.150 m standardized sodium hydroxide solution. the endpoint was reached when 18.80

Arte-miy333 [17]

18.80 mL) x (0.150 M) / (25.00 mL) = 0.113 M

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3 years ago

The most condensed state of matter is A. solid B. liquid C. gas D. plasma

algol [13]

The most condensed state of matter is A. Solid Matter

6 0

4 years ago

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A compound composed of only carbon and chlorine is 85.5% chlorine by mass. propose a lewis structure for the lightest of the pos

aivan3 [116]

Answer is in picture below.

Use 100 grams of the compound:

ω(Cl) = 85.5% ÷ 100%.

ω(Cl) = 0.855; mass percentage of the chlorine in the compound.

m(Cl) = 0.855 · 100 g.

m(Cl) = 85.5 g; mass of chlorine.

m(C) = 100 g - 85.5 g.

m(C) = 14.5 g; mass of carbon.

n(Cl) = m(Cl) ÷ M(Cl).

n(Cl) = 85.5 g ÷ 35.45 g/mol.

n(Cl) = 2.41 mol; amount of chlorine.

n(C) = 14.5 g ÷ 12 g/mol.

n(C) = 1.21 mol; amount of carbon.

n(Cl) : n(C) = 2.41 mol : 1.21 mol = 2 : 1.

This compound is dichlorocarbene CCl₂.

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3 years ago

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