Answer:
The answer to your question is : letter B. 0.25 atm
Explanation:
To solve this problem we need to use the combined gas law:
<u>P₁V₁</u> = <u>P₂V₂</u>
T₁ T₂
Data
P1 = 0.99 atm V1 = 2 l T1 = 273K
P2 = ? V2 = 4 l T2 = 137K
Now, the clear P2 from the equation and we get
P2 = P1V1T2 / T1V2
Substitution P2 = (2 x 0.99 x 137)/(273 x 4)
P2 = 271.26 / 1092
Result P2 = 0.248 atm ≈ 0.25 atm
Answer:
The orbital notations shows the sequence of filling electrons into the orbitals of sublevels. This filling is based on some certain principles. For an atom with 16 electrons, the orbital diagram is shown below: 1s²2s²2p⁶3s²3p⁴ The maximum number of electrons in each sublevel of the orbitals are: 2 electrons for s-sublevel with one orbital
6 electrons for p-sublevel with three orbital
10 electrons for d-sublevel with five orbital
14 electrons for f-sublevel with seven orbital
According to the Aufbau's principle, sublevels with lower energy are filled before those with higher energy.
1s 2s 2p 3s 3p 4s 3d etc
Pauli's exclusion principle shows that no two electrons can have the same set of values for the four quantum numbers. Simply, no two electrons can spin in the same direction. Hund's rule states that electrons go into degenerate orbitals of sub-levles(s,p,d and f) singly before pairing commence. This rule shows that in each energy level, as the electron goes into the degenerate orbitals, they fill it one by one before they begin to pair up. As we know, each degenerate orbital can only accomodate 2 electrons. From the orbital diagram 1s²2s²2p⁶3s²3p⁴, the 3p sublevel has 3 orbitals. In each of the orbitals, two electrons would occupy them to give a maximum capacity of 6. But the sublevel has just 4 electrons. Based on Hund's rule, an electron will go into each of the 3 orbitals first. The remaining electron will now pair with the first degenerate orbital. This makes a total of 4 electrons.
Explanation:
