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AnnZ [28]
3 years ago
10

Adam takes a bus on a school field trip. The bus route is split into the five legs listed in the table. Find the average velocit

y for each leg of the trip. Then arrange the legs of
the trip from highest velocity to lowest.
Leg Distance (km) Time (min)
А 18
9
B
25
15
С
24
8
D
48
12
E
15
7
leg A
leg B
leg c
leg D
leg E
Physics
1 answer:
Tema [17]3 years ago
7 0

Answer:

leg D → leg C → leg E → leg A →leg B

Explanation:

PLEASE VOTE ME BRAINLYIEST!!!!!!!!

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What pulls all objects in the universe, including the moon and earth and the su
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A person hits a 45-g golf ball. The ball comes down on a tree root and bounces
Verizon [17]

Answer:

Maximum height, h = 10 m          

Explanation:

It is given that,

Mass of golf ball, m = 45 g = 0.045 kg

The ball comes down on a tree root and bounces  straight up with an initial speed of 14.0 m/s.

We need to find the height the ball will rise  after the bounce. It is based on the conservation of energy such that,

\dfrac{1}{2}mv^2=mgh

h is maximum height raised by the ball

h=\dfrac{v^2}{2g}\\\\h=\dfrac{(14)^2}{2\times 9.8}\\\\h=10\ m

So, the ball will raised to a height of 10 meters.

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There are two possibilities for final stage of extremely massive stars. The first is a
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What is the quantity of heat energy required to convert 10g cube of ice at -30oC to steam at 120oC. also draw a graph of tempera
Nadusha1986 [10]

Answer:

The amount of energy required is 31.1692 kJ .

Explanation:

The transitions of water are as follows,

(243K ice to 273K ice to 273K water to 373k water to 373K steam to 393K steam)

The following required data is,

specific heat capacity of ice= 2.1 kJ/kg

specific heat capacity of water= 4.2 kJ/kg

specific heat capacity of ice= 1.996 kJ/kg

specific latent heat of fusion=334 kJ/kg

specific latent heat of vapourisation = 2260 kJ/kg

FORMULAS:-

temperature change=mc(T2-T1)

phase transistion = mL,

where, m=mass , c=specific heat capacity ,L = latent heat of fusion or vapourisation ,(T2-T1)= temparature change

Thus the total amount of heat is,

=mc(T4-T3) + mL + mc(T3-T2) + mL + mc(T2-T1)

=10(10^{-3} )(2.1)(30)+10(10^{-3} )(334)+10(10^{-3} )(100)(4.2)+10(10^{-3} )(2260) +10(10^{-3} )(20)(1.996)

=(0.3)(2.1) + (3.34) + (4.2) +  (22.6) + (0.2)(1.996)

=31.1692 kJ.

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Read 2 more answers
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