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AnnZ [28]
3 years ago
10

Adam takes a bus on a school field trip. The bus route is split into the five legs listed in the table. Find the average velocit

y for each leg of the trip. Then arrange the legs of
the trip from highest velocity to lowest.
Leg Distance (km) Time (min)
А 18
9
B
25
15
С
24
8
D
48
12
E
15
7
leg A
leg B
leg c
leg D
leg E
Physics
1 answer:
Tema [17]3 years ago
7 0

Answer:

leg D → leg C → leg E → leg A →leg B

Explanation:

PLEASE VOTE ME BRAINLYIEST!!!!!!!!

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A force of 5 N accelerates an object. The object’s mass is 50 g. What is the acceleration of the object? (Formula: F=ma)
goldfiish [28.3K]

Answer:

100 m/s²

Explanation:

First, convert to SI units:

50 g = 0.050 kg

Now plug into the formula:

F = ma

5 N = (0.050 kg) a

a = 100 m/s²

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4 years ago
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3 0
3 years ago
A package is dropped from an airplane flying at an altitude of 69.2 m with a velocity of 1.40 x 10^2 km/h. Calculate the horizon
Andrew [12]
69.2 m with a velocity of 1.40* 10^2 km/h.

5 0
4 years ago
You're driving down the highway late one night at 20 m/s when a deer steps onto the road 35 m in front of you. You reaction time
bearhunter [10]

Answer:

Explanation:

Discount the time here; it's not important. It doesn't tell you how long it takes the car to stop, it only refers to reaction time, which means nothing in the scheme of things.

The useful info is as follows:

initial velocity = 20 m/s

final velocity = 0 m/s

a = -10 m/s/s

and we are looking for the displacement. Use the following equation:

v^2=v_0^2+2aΔx

where v is the final velocity, v₀ is the initial velocity, a is the deceleration (since it's negative), and Δx is displacement. Filling in:

0^2=(20)^2+2(-10)Δx and

0 = 400 - 20Δx and

-400 = -20Δx so

Δ = 20 meters

3 0
3 years ago
A rock is dropped (from rest) off a bridge over the Merrimack River. The falling rock
rewona [7]

Answer:

31.25 meters or ~31 meters approximately

Explanation:

Let's see which of the 5 variables we are given since this is a constant acceleration problem.

  • v_i  \ \ \ \ \ \  t \\ v_f \ \ \ \ \ \triangle x \\ a

We want to find the height of the bridge, aka the vertical displacement of the rock. Let's set the upwards direction to be positive and the downwards direction to be negative.

We are told that the acceleration is 10 m/s² downward, so we have a = -10 m/s².

We are also told that the time it takes the rock to hit the water is 2.5 seconds. Time is the same regardless of the x- or y- direction, so we can say that t = 2.5 seconds.

Now, we aren't told this directly, but we can figure out that the velocity in the y-direction is 0 m/s, since the rock is dropped from rest off the bridge. Therefore, v_i=0 \frac{m}{s}.

We want to find the vertical displacement, the height of the bridge, so we can say that \triangle x= \ ?

We have 4 out of 5 variables:

  • v_i,\ a, \ t, \ \triangle x

Look through the constant acceleration equations to see which equation has all 4 of these variables. You should come up with this one (no final velocity):

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Subtract x_i from both sides of the equation to get:

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Substitute in our known variables and solve for delta x.

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0 m/s multiplied by 2.5 s is 0, so we have:

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Evaluate the exponent first and multiply the terms together.

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  • \triangle x =-31.25

The vertical displacement is -31.25 meters from the rock's starting position, so we can say that the height of the bridge is 31.25 meters, which is approximately 31 meters tall.

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3 years ago
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