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muminat
3 years ago
9

A pharmacist measures the mass of a powdered drug. The mass is 506 mg . What is the mass in grams? Write your answer as a decima

l.
Chemistry
1 answer:
otez555 [7]3 years ago
8 0

Answer:

0.506 g

Explanation:

we know that one miligram is equal to 0.001 g or we can say that  one gram contain thousand miligram. so,

if the mass of drug is 506 mg then to convert it into gram we have to divide 506 mg into 1000.  

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A bottle containing 415 g of cleaning solution is used to clean hospital equipment. If the cleaning solution has a specific grav
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Answer: 483 mL of the cleaning solution are used to clean hospital equipment

Explanation:

The question requires us to calculate the volume, in mL, of solution is used to clean hospital equipment, given that 415g of this solution are used and the specific gravity of the solution is 0.860.

Measurements > Density

Specific gravity is defined as the ratio between the density of a given substance to the density of a reference material, such as water:

Specific\text{ gravity = }\frac{density\text{ of substance}}{density\text{ of reference substance}}

The density of a substance is defined as the ratio between the mass and the volume of this substance:

density=\frac{mass}{volume}

Considering the reference substance as water and its density as 1.00 g/mL, we can determine the density of the substance which specific gravity is 0.860:

0.860=\frac{density\text{ of substance}}{1.00g/mL}\rightarrow density\text{ of substance = 0.860g/mL}

Thus, taking water as the reference substance, we can say that the density of the cleaning solution is 0.860 g/mL.

Now that we know the density of the cleaning solution (0.860 g/mL) and the mass of solution that is used to clean hospital equipment (415g), we can calculate the volume of solution that is used to clean the equipment:

\begin{gathered} density=\frac{mass}{volume}\rightarrow volume=\frac{mass}{density} \\  \\ volume=\frac{415g}{0.860g/mL}=483mL \end{gathered}

Therefore, 483 mL of the cleaning solution are used to clean hospital equipment.

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1 year ago
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If a student has 125 mL of a 4.00 M CuSO4 solution and needs a 1.50 M solution, what volume do they need to dilute it to?
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Answer:

333.3mL

Explanation:

Using the formula as follows:

C1V1 = C2V2

Where;

C1 = initial concentration (M)

C2 = final concentration (M)

V1 = initial volume (mL)

V2 = final volume (mL)

According to the information provided in this question,

C1 = 4.00M

C2 = 1.50M

V1 = 125mL

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4 × 125 = 1.5 × V2

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V2 = 500/1.5

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Therefore, the CuSO4 solution needs to be diluted to 333.3mL to make 1.50 M solution.

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2 years ago
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