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3 years ago

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A pharmacist measures the mass of a powdered drug. The mass is 506 mg . What is the mass in grams? Write your answer as a decima

l.

1 answer:

otez555 [7]3 years ago

8 0

Answer:

0.506 g

Explanation:

we know that one miligram is equal to 0.001 g or we can say that one gram contain thousand miligram. so,

if the mass of drug is 506 mg then to convert it into gram we have to divide 506 mg into 1000.

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Magnesium + Nitrogen ➡ Magnesium Nitrate

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Explain why an insoluble compound added to water is considered a nonelectrolyte.

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Explanation:

A non-electrolyte is defined as a solution which does not contain any ions and hence, it is unable to conduct electricity.

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As electricity is the flow of ions or electrons. So, a non-electrolyte solution is not able to conduct electricity.

Similarly, a compound that is insoluble in water will not dissociate into ions. Hence, this type of solution will not be able to conduct electricity.

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A galvanic cell consists of a Cu(s)|Cu2+(aq) half-cell and a Cd(s)|Cd2+(aq) half-cell connected by a salt bridge. Oxidation occu

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Answer:

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Explanation:

A galvanic cell is composed of two electrodes immersed in a suitable electrolyte and connected via a salt bridge. One of the electrodes serves as a cathode where reduction or gain of electrons takes place. The other half cell functions as an anode where oxidation or loss of electrons occurs.

The representation is given by writing the anode on left hand side followed by its ion with its molar concentration. It is followed by a salt bridge. Then the cathodic ion with its molar concentration is written and then the cathode.

As it is given that cadmium acts as anode, it must be on the left hand side and copper must be on right hand side.

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Explanation:

The reaction equation will be as follows.

$CO_{2}(aq) + H_{2}O \rightleftharpoons H^{+}(aq) + HCO^{-}_{3}(aq)$

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$CO_{2}(aq) = K_{CO_{2}} \times P_{CO_{2}}$

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Hence, $[CO_{2}]$ will be calculated as follows.

$[CO_{2}]$ = $K_{CO_{2}} \times P_{CO_{2}}$

= $0.032 M/atm \times 1.9 \times 10^{-4}atm$

= $0.0608 \times 10^{-4}$

or, = $0.608 \times 10^{-5}$

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As, $K_{a} = \frac{[H^{+}]^{2}}{[CO_{2}]}$

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Since, we know that pH = $-log [H^{+}]$

So, pH = $-log (1.64 \times 10^{-6})$

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