Answer:
<em>The balloon is 66.62 m high</em>
Explanation:
<u>Combined Motion
</u>
The problem has a combination of constant-speed motion and vertical launch. The hot-air balloon is rising at a constant speed of 14 m/s. When the camera is dropped, it initially has the same speed as the balloon (vo=14 m/s). The camera has an upward movement for some time until it runs out of speed. Then, it falls to the ground. The height of an object that was launched from an initial height yo and speed vo is

The values are


We must find the values of t such that the height of the camera is 0 (when it hits the ground)


Multiplying by 2

Clearing the coefficient of 

Plugging in the given values, we reach to a second-degree equation

The equation has two roots, but we only keep the positive root

Once we know the time of flight of the camera, we use it to know the height of the balloon. The balloon has a constant speed vr and it already was 15 m high, thus the new height is



Answer:
<h3>The answer is 3.81 kg</h3>
Explanation:
The mass of the dog can be found by using the formula

f is the force
a is the acceleration
From the question we have

We have the final answer as
<h3>3.81 kg</h3>
Hope this helps you
<span>b. It ensures that measurements are taken from two points
that are very far apart.
Measurements taken six months apart are the farthest apart
that an astronomer can ever get ... they're on opposite sides
of the Earth's orbit !</span>
Its either B. force or A. net force but I will go with force because forces can either push or pull I hope it help you.