The answer is 10,560 Joules or 1.1*10^4
Explanation:
Step 1: Calculate
The equation for Kinetic Energy is
Kinetic energy=.5 times Mass times Velocity²
KE=.5*m*v²
so we plug in our numbers
KE=.5*600*35.2²
This works out to be 10,560 Joules or 1.1*10^4
Answer:
the impulse experienced by the egg is 0.053 kgm/s.
Explanation:
Given;
mass of the egg, m = 60 g = 0.06 kg
initial velocity of the egg, u = 6 m/s
height moved by the egg, h = 50 cm = 0.5 m
Determine the final velocity of the egg as it moves upward;
v² = u² + 2(-g)h
v² = u² - 2gh
where;
v is the final velocity
-g is negative acceleration due gravity as it moves upward
v² = 6² - 2(9.8 x 0.5)
v² = 26.2
v = √26.2
v = 5.12 m/s
The impulse applied to the egg is the change in linear momentum;
J = ΔP
ΔP = mu - mv
ΔP = m(u - v)
ΔP = 0.06(6 - 5.12)
ΔP = 0.053 kgm/s
Therefore, the impulse experienced by the egg is 0.053 kgm/s.
The Atomic Number is equal to the amount of Protons and Electrons. To find the amount of Neutrons in an atom, you have to look at the Mass Number. The Mass Number is the SUM (_+_=_) of Protons and Neutrons in an atom. In this case, you will have to make up equations. For example: Argon. Argon's Mass Number is 40. You need to find the amount of Protons in the atom (18). Mass Number (40) - Protons (18) = Amount of Neutrons. 40-18=22.
Argon has 22 Neutrons, because Protons(18)+Neutrons(22)=Mass Number(40).
Hope I could help!
Answer:
1) The plane of the loop is perpendicular to the magnetic field.
2) The magnetic flux is independent of the orientation of the loop.p
Explanation:
The flux is calculated as φ=BAcosθ. The flux is therefore the highest when the magnetic field vector is perpendicular to the plane of the loop We can also deduce that the flux is zero when there is no magnetic field part perpendicular to the loop When the angle reaches zero, the flux is in the limit because when the angle becomes zero, the cos is the maximum.
Explanation:
They probably put "rolls without slipping" in there to indicate that there is no loss in friction; or that the friction is constant throughout the movement of the disk. So it's more of a contingency part of the explanation of the problem.
(Remember how earlier on in Physics lessons, we see "ignore friction" written into problems; it just removes the "What about [ ]?" question for anyone who might ask.)
In this case, you can't ignore friction because the disk wouldn't roll without it.
As far as friction producing a torque... I would say that friction is a result of the torque in this case. And because the point of contact is, presumably, the ground, the friction is tangential to the disk. Meaning the friction is linear and has no angular component.
(You could probably argue that by Newton's 3rd Law there should be some opposing torque, but I think that's outside of the scope of this problem.)
Hopefully this helps clear up the misunderstanding for you.
