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weqwewe [10]
2 years ago
12

A bus is moving in astraight line at speed of 25m/s. What time does bus take to cover 5 km

Physics
1 answer:
WARRIOR [948]2 years ago
5 0

Answer:

Kinematics

given,

time (t)=100 s, distance (s)=1 km=1000 m

V

b

=10m/s (relative speed r.p to bus)

Velocity (v)=

time

distance

=

100

1000

V

s

= velocity of scooter

V

b

→ Velocity of bus

V=V

s

−V

b

→As we know

10=V

s

−10

20=V

s

V

s

=20 m/s

Velocity with which scooterist

should chase the bus →20 m/s

Explanation:

I Hope you Guys Understood

please mark as Brainliest....

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If it requires 3.0 J of work to stretch a particular spring by 2.1 cm from its equilibrium length, how much more work will be re
-BARSIC- [3]

Answer:

Work done = 13605.44

Explanation:

Data provided in the question:

For elongation of 2.1 cm (0.021 m) work done by the spring is 3.0 J

The relation between Energy (U) and the elongation (s) is given as:

U = \frac{1}{2}kx^2   ................(1)

where,

k is the spring constant

on substituting the valeus in the above equation, we get

3.0 = \frac{1}{2}k\times0.021^2

or

k = 13605.44 N/m

now

for the elongation x = 2.1 + 4.1 = 6.2 cm = 0.062 m

using the equation 1, we have

U = \frac{1}{2}\times13605.44\times (0.062)^2

or

U = 26.149 J

Also,

Work done = change in energy

or

W = 26.149 - 3.0 = 23.149 J

4 0
2 years ago
The acceleration vector of a particle in projectile motion ________.
Alex73 [517]

Answer:

Points downward, and its magnitude is 9.8 m/s^2

Explanation:

The motion of a projectile consists of two independent motions:

- A uniform horizontal motion, with constant velocity and zero acceleration. In fact, there are no forces acting on the projectile along the horizontal direction (if we neglect air resistance), so the acceleration along this direction is zero.

- A vertical motion, with constant acceleration g = 9.8 m/s^2 towards the ground (downward), due to the presence of gravity wich "pulls" the projectile downward.

The total acceleration of the projectile is given by the resultant of the horizontal and vertical components of the acceleration. But we said that the horizontal component is zero, therefore the total acceleration corresponds just to its vertical component, therefore it is a vector with magnitude 9.8 m/s^2 which points downward.

4 0
2 years ago
A 4 kg bird is flying with a velocity of 4 m/s. What is its kinetic energy?
Maslowich
32 kg m/s would be the kinetic energy.
3 0
3 years ago
What is the magnitude of the total acceleration of point A after 2 seconds? The bar starts from rest and has a constant angular
monitta

Answer:

a_total = 2 √ (α² + w⁴) ,   a_total = 2,236 m

Explanation:

The total acceleration of a body, if we use the Pythagorean theorem is

          a_total² = a_T²2 + a_{c}²

where

the centripetal acceleration is

  a_{c} = v² / r = w r²

tangential acceleration

   a_T = dv / dt

angular and linear acceleration are related

         a_T = α  r

we substitute in the first equation

       a_total = √ [(α r)² + (w r² )²]

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Let's find the angular velocity for t = 2 s if we start from rest wo = 0

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we substitute

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In order to finish the calculation we need the radius to point A, suppose that this point is at a distance of r = 1 m

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7 0
3 years ago
Two trains are traveling side-by-side along parallel, straight tracks at the same speed. In a time t, train A doubles its speed.
sergij07 [2.7K]

Answer:

derdddrdickdd

Explanation:

3 0
3 years ago
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