All categories

2 years ago

A bus is moving in astraight line at speed of 25m/s. What time does bus take to cover 5 km

Physics

1 answer:

WARRIOR [948]2 years ago

5 0

Answer:

Kinematics

given,

time (t)=100 s, distance (s)=1 km=1000 m

=10m/s (relative speed r.p to bus)

Velocity (v)=

time

distance

100

1000

= velocity of scooter

→ Velocity of bus

V=V

−V

→As we know

10=V

−10

20=V

=20 m/s

Velocity with which scooterist

should chase the bus →20 m/s

Explanation:

I Hope you Guys Understood

please mark as Brainliest....

You might be interested in

What to do if vehicle struck by lightning

agasfer [191]

Lighting flows around the outside of a truck, and the majority of the current flows from the cars metal cage into the ground below. It's not very safe to be in a car or truck during bad weather.

4 0

3 years ago

How much heat is needed to vaporize 10.00 grams of water at 100.0°C? The latent heat of vaporization of water is 2,259 J/g

Nata [24]

Answer:

Heat of vaporization will be 22.59 j

Explanation:

We have given mass m = 10 gram

And heat of vaporization L = 2.259 J/gram

We have to find the heat required to vaporize 10 gram mass

We know that heat of vaporization is given by $Q=mL$ , here m is mass and L is latent heat of vaporization.

So heat of vaporization Q will be = 10×2.259 = 22.59 J

8 0

3 years ago

Read 2 more answers

Atoms of which two elements could combine with atoms of chromium (Cr) to

Sergio039 [100]

Answer:

D and E

Ionic bonds are formed between metals and non-metals and both of those are metals

4 0

2 years ago

If I wanted to generate a maximum emf of 20 V, what angular velocity (radians/sec, aka Hz) would be required given a circular co

sergij07 [2.7K]

Answer:

Angular velocity, $\omega=35.36\ rad/s$

Explanation:

It is given that,

Maximum emf generated in the coil, $\epsilon=20\ V$

Diameter of the coil, d = 40 cm

Radius of the coil, r = 20 cm = 0.2 m

Number of turns in the coil, N = 500

Magnetic field in the coil, $B=9\times 10^{-3}\ T$

The angle between the area vector and the magnet field vector varies from 0 to 2 π radians. The formula for the maximum emf generated in the coil is given by :

$\epsilon=NBA\omega$

$\omega=\dfrac{\epsilon}{NBA}$

$\omega=\dfrac{20\ V}{500\times 9\times 10^{-3}\ T\times \pi (0.2\ m)^2}$

$\omega=35.36\ rad/s$

So, the angular velocity of the circular coil is 35.36 rad/s. Hence, this is the required solution.

6 0

3 years ago

Jason places his economics book (3 kg) on a level table. He then puts his calculus book (5 kg) on top of the economics book, the

lilavasa [31]

Nothing is accelerating ... it's not even moving. Everything is just sitting there.
That right there tells you that the forces are balanced wherever two things meet,
otherwise something would be accelerating.

At each level where two things meet, there are 2 forces:

-- The gravitational force ... the weight of everything above that place,
and
-- The upward force, exerted by everything below that place.

Here is the stack:
_____________
| Physics ... 2kg | weight = M G = 2 x 9.8 = 19.6 newtons
---------------------
|Calculus ..5 kg | weight = M G = 5 x 9.8 = 49 newtons
---------------------
|Econ . . . .3 Kg | weight = M G = 3 x 9.8 = 29.4 newtons
==================
-------- (Table) ----------
/ \

a). Surface where the table meets the Economics book.
Weight of everything above = (29.4 + 49 + 19.6) = 98 newtons
Upward force exerted on the Econ book by the table = 98 newtons.

b). Surface where the Econ book meets the Calculus book.
Weight of everything above = (49 + 19.6) = 68.6 newtons.
Upward force exerted on the Calc book by the Econ book = 68.6 newtons.

c). Surface where the Calculus book meets the Physics book.
Weight of everything above = 19.6 newtons.
Force exerted on the Physics book by the Calc book = 19.6 newtons.

6 0

3 years ago