S=Vt
110=V(72)
110/72=V
V=1.527m/s
I would choose B. exosphere. Astronomers study outer space, planets and ect.
Answer:
Explanation:
If a baseball is hit into the air with a velocity of 27 m/s, we want to determine the maximum height of the ball. Using the projecile formula;
Max height H = u²/2g
u is the initial velocity of the body = 27m/s
g is the acceleration due to gravity = 9.81m/s²
H = 27²/2(9.81)
H = 729/19.62
H = 37.16m
Hence the ball went 37.16m high
Answer:
a) τ = 0.672 N m
, b) θ = 150 rad
, c) W = 100.8 J
Explanation:
a) for this part let's start by finding angular acceleration, when the angular velocity stops it is zero (w = 0)
w = w₀ + α t
α = -w₀ / t
α = 120 / 2.5
α = 48 rad / s²
The moment of inertia of a cylinder is
I = ½ M R²
Let's calculate the torque
τ = I α
τ = ½ M R² α
τ = ½ 2.8 0.1² 48
τ = 0.672 N m
b) we look for the angle by kinematics
θ = w₀ t + ½ α t2
θ = ½ α t²
θ = ½ 48 2.5²
θ = 150 rad
c) work in angular movement
W = τ θ
W = 0.672 150
W = 100.8 J
