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klio [65]
3 years ago
12

Listening to the radio, you can hear two stations at once. Describe this wave interaction

Physics
2 answers:
vodka [1.7K]3 years ago
4 0

That situation is called <em>interference </em>.

cupoosta [38]3 years ago
4 0

Answer: The correct answer is "interference".

Explanation:

Interference: It is a phenomenon in which there is a superposition or a overlapping of the waves occur in the same medium. The resulting wave may have minimum amplitude or maximum amplitude. The interference can be : constructive and destructive depending on the amplitude of the resulting wave.

When the frequencies of the waves are not identical but they are similar interfere then the resulting wave is a beat frequency. Beat frequency is a pulsing sound. It goes up and down in loudness.

When you listen to the radio, you hear two stations at once. This interaction of this wave is interference.

Therefore, the correct option is (B).

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krek1111 [17]

Answer:

C

Explanation:

4 0
3 years ago
Two cars leave Calgary at the same time, travelling in opposite directions. Their average speeds differ by 5 km/h. After 2 h, th
dimulka [17.4K]
Let the first car's average speed be x

The second car's speed would be x+5

2(x+(x+5))=210

2x+5=105

2x=100

x=50

So the speed of the slower car is 50mph, and the speed of the faster car is 55mph


8 0
3 years ago
Read 2 more answers
You pick up a 3.4-kg can of paint from the ground and lift it to a height of 1.8 m. (a) how much work do you do on the can of pa
MariettaO [177]

(a) For the work-energy theorem, the work done to lift the can of paint is equal to the gravitational potential energy gained by it, therefore it is equal to

W=mg\Delta h

where m=3.4 kg is the mass of the can, g=9.81 m/s^2 is the gravitational acceleration and \Delta h=1.8 m is the variation of height. Substituting the numbers into the formula, we find

W=(3.4 kg)(9.81 m/s^2)(1.8 m)=60.0 J


(b) In this case, the work done is zero. In fact, we know from its definition that the work done on an object is equal to the product between the force applied F and the displacement:

W=Fd

However, in this case there is no displacement, so d=0 and W=0, therefore the work done to hold the can stationary is zero.


(c) In this case, the work done is negative, because the work to lower the can back to the ground is done by the force of gravity, which pushes downward. Its value is given by the same formula used in part (a):

W=mg \Delta h=(3.4 kg)(9.81 m/s^2)(-1.8 m)=-60.0 J

8 0
4 years ago
A force of 100 newtons Is applled to a box at an angle of 36° with the horizontal. If the mass of the box Is 25 kilograms, what
faust18 [17]
Horizontal component of force = 100cos(36)= 80.9 N
5 0
3 years ago
A 1kg ball is dropped (from rest) 100m onto a spring with spring constant 125N/m. How much does the spring compress?
Anastasy [175]

Answer:

3.95 m

Explanation:

m = 1 kg, h = 100 m, k = 125 N/m

Let the spring is compressed by y.

Use the conservation of energy

potential energy of the mass is equal to the energy stored in the spring

m x g x h = 1/2 x ky^2

1 x 9.8 x 100 = 0.5 x 125 x y^2

y^2 = 15.68

y = 3.95 m

7 0
4 years ago
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